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Ch. 3 - Derivatives
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243당신이 사용하는 게 아니라요?교과서 변경
3장, 문제 8a

Find the derivative the following ways:
Using the Product Rule or the Quotient Rule. Simplify your result.
g(t) = (t + 1)(t² - t + 1)

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1
Identify the function as a product of two functions: \( u(t) = t + 1 \) and \( v(t) = t^2 - t + 1 \).
Recall the Product Rule for derivatives, which states: \( (uv)' = u'v + uv' \).
Find the derivative of \( u(t) = t + 1 \), which is \( u'(t) = 1 \).
Find the derivative of \( v(t) = t^2 - t + 1 \), which is \( v'(t) = 2t - 1 \).
Apply the Product Rule: \( g'(t) = u'(t)v(t) + u(t)v'(t) = 1(t^2 - t + 1) + (t + 1)(2t - 1) \). Simplify the expression to get the final derivative.

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주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Product Rule

The Product Rule is a formula used to find the derivative of the product of two functions. If you have two functions, u(t) and v(t), the derivative of their product is given by u'v + uv'. This rule is essential when differentiating expressions where two functions are multiplied together, as it allows for a systematic approach to finding the derivative.
추천 영상:
05:18
The Product Rule

Quotient Rule

The Quotient Rule is used to differentiate a function that is the quotient of two other functions. If f(t) = u(t)/v(t), the derivative is given by (u'v - uv')/v². This rule is particularly useful when dealing with fractions of functions, ensuring that the differentiation accounts for both the numerator and the denominator.
추천 영상:
06:43
The Quotient Rule

Simplification of Derivatives

After applying the Product or Quotient Rule, the resulting derivative often needs simplification to make it more manageable or interpretable. This involves combining like terms, factoring, or reducing fractions. Simplification is crucial for clearer analysis and understanding of the behavior of the function, especially when evaluating limits or finding critical points.
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