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Ch. 4 - Applications of the Derivative
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243당신이 사용하는 게 아니라요?교과서 변경
4장, 문제 3.8.13a

13-26 Implicit differentiation Carry out the following steps.
a. Use implicit differentiation to find dy/dx.
x⁴+y⁴ = 2;(1,−1)

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Start by differentiating both sides of the equation \(x^4 + y^4 = 2\) with respect to \(x\). Remember that \(y\) is a function of \(x\), so you'll need to use implicit differentiation for terms involving \(y\).
Differentiate \(x^4\) with respect to \(x\) to get \(4x^3\).
Differentiate \(y^4\) with respect to \(x\) using the chain rule. This gives \(4y^3 \frac{dy}{dx}\).
Set the derivative of the left side equal to the derivative of the right side, which is zero, since the derivative of a constant is zero: \(4x^3 + 4y^3 \frac{dy}{dx} = 0\).
Solve for \(\frac{dy}{dx}\) by isolating it on one side of the equation: \(\frac{dy}{dx} = -\frac{x^3}{y^3}\). Finally, substitute the point \((1, -1)\) into the expression to find the specific value of \(\frac{dy}{dx}\) at that point.

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이 영상 해법은 위 문제에 도움이 된다고 튜터들이 추천한 것입니다.
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주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Implicit Differentiation

Implicit differentiation is a technique used to differentiate equations where the dependent and independent variables are not explicitly separated. Instead of solving for y in terms of x, we differentiate both sides of the equation with respect to x, treating y as a function of x. This method allows us to find the derivative dy/dx without isolating y, which is particularly useful for complex equations.
추천 영상:
05:14
Finding The Implicit Derivative

Chain Rule

The chain rule is a fundamental principle in calculus that allows us to differentiate composite functions. When using implicit differentiation, we apply the chain rule to account for the derivative of y with respect to x, denoted as dy/dx. This means that when differentiating terms involving y, we multiply by dy/dx to correctly represent the relationship between the variables.
추천 영상:
05:02
Intro to the Chain Rule

Evaluating Derivatives at a Point

After finding the expression for dy/dx through implicit differentiation, we often need to evaluate this derivative at a specific point, such as (1, -1) in this case. This involves substituting the x and y values into the derived expression to find the slope of the tangent line at that point. This step is crucial for understanding the behavior of the function at specific coordinates.
추천 영상:
04:50
Critical Points