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Ch. 5 - Integration
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243당신이 사용하는 게 아니라요?교과서 변경
5장, 문제 5.5.70

Definite integrals Use a change of variables or Table 5.6 to evaluate the following definite integrals.                                                                                                                         
                                                                                                                                                                              
 ∫₋₁¹ (𝓍―1) (𝓍²―2𝓍)⁷ d𝓍

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Step 1: Recognize that the integral ∫₋₁¹ (𝓍 - 1)(𝓍² - 2𝓍)⁷ d𝓍 involves a composite function (𝓍² - 2𝓍) raised to a power. This suggests using a substitution method to simplify the integral.
Step 2: Let u = 𝓍² - 2𝓍. Compute the derivative of u with respect to 𝓍: du/d𝓍 = 2𝓍 - 2. Rewrite this as du = (2𝓍 - 2)d𝓍.
Step 3: Factorize the original integral to match the substitution. Notice that (𝓍 - 1) can be factored out from the derivative du = (2𝓍 - 2)d𝓍, since (𝓍 - 1) is a common factor. Rewrite the integral in terms of u.
Step 4: Change the limits of integration. When 𝓍 = -1, substitute into u = 𝓍² - 2𝓍 to find the lower limit of u. Similarly, when 𝓍 = 1, substitute into u = 𝓍² - 2𝓍 to find the upper limit of u.
Step 5: Rewrite the integral entirely in terms of u and evaluate using standard integration techniques or a table of integrals. After integration, substitute back the original variable if necessary.

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주요 개념

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Definite Integrals

A definite integral represents the signed area under a curve defined by a function over a specific interval [a, b]. It is calculated using the Fundamental Theorem of Calculus, which connects differentiation and integration. The result of a definite integral is a number that quantifies the accumulation of quantities, such as area, volume, or total change, between the limits of integration.
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05:43
Definition of the Definite Integral

Change of Variables

Change of variables, or substitution, is a technique used in integration to simplify the integrand by transforming it into a more manageable form. This involves substituting a new variable for an existing one, which can make the integral easier to evaluate. The process requires adjusting the limits of integration and the differential to maintain the integrity of the integral's value.
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06:35
Changing Geometries

Integration Techniques

Integration techniques encompass various methods used to evaluate integrals, including substitution, integration by parts, and using tables of integrals. These techniques are essential for solving complex integrals that cannot be evaluated using basic antiderivatives. Familiarity with these methods allows students to tackle a wide range of problems in calculus effectively.
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06:18
Integration by Parts for Definite Integrals
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교과서 질문

Derivatives of integrals Simplify the following expressions.


d/dt ∫₀ᵗ d𝓍/(1 + 𝓍²) + ∫₁¹/ᵗ dx/(1 + 𝓍²)

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교과서 질문

Integrals with sin² 𝓍 and cos² 𝓍 Evaluate the following integrals.                                                                                                             

                                                                                                                                                                    

 ∫ 𝓍 cos²𝓍² d𝓍

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교과서 질문

Symmetry of composite functions Prove that the integrand is either even or odd. Then give the value of the integral or show how it can be simplified. Assume f and g are even functions and p and q are odd functions.


∫ᵃ₋ₐ ƒ(g(𝓍)) d𝓍

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교과서 질문

Suppose the interval [1, 3] is partitioned into n = 4 subintervals. What is the subinterval length ∆𝓍? List the grid points x₀ , x₁ , x₂ , x₃ and x₄. Which points are used for the left, right, and midpoint Riemann sums?

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교과서 질문

Left and right Riemann sums Use the figures to calculate the left and right Riemann sums for f on the given interval and for the given value of n.

ƒ(𝓍) = x + 1 on [1,6] ; n = 5

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교과서 질문

Use the given substitution to evaluate the following indefinite integrals. Check your answer by differentiating.                                                                                              

                                                                                                                                                                                       

 ∫ 8𝓍 cos (4𝓍² + 3) d𝓍, u = 4𝓍² + 3

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