Evaluating integrals Evaluate the following integrals.

∫₀² (2𝓍 + 1)³ d𝓍

검증된 단계별 안내

Step 1: Recognize that the integral ∫₀² (2𝓍 + 1)³ d𝓍 involves a polynomial raised to a power. To simplify, consider using substitution. Let u = 2𝓍 + 1, which transforms the integral into a simpler form.

Step 2: Compute the derivative of u with respect to 𝓍: du/d𝓍 = 2. Rearrange to express du in terms of d𝓍: du = 2 d𝓍.

Step 3: Adjust the limits of integration to match the substitution. When 𝓍 = 0, u = 2(0) + 1 = 1. When 𝓍 = 2, u = 2(2) + 1 = 5. The integral now becomes ∫₁⁵ u³ (1/2) du, where the factor 1/2 comes from the substitution for d𝓍.

Step 4: Factor out the constant 1/2 from the integral: (1/2) ∫₁⁵ u³ du. Now, apply the power rule for integration: ∫ uⁿ du = (uⁿ⁺¹)/(n+1) + C, where n is the exponent.

Step 5: Use the power rule to integrate u³: (1/2) [(u⁴)/4] evaluated from u = 1 to u = 5. Substitute the limits into the result to complete the evaluation.

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주요 개념

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Definite Integrals

A definite integral represents the signed area under a curve defined by a function over a specific interval. In this case, the integral ∫₀² (2𝓍 + 1)³ d𝓍 calculates the area between the curve (2𝓍 + 1)³ and the x-axis from x = 0 to x = 2. The limits of integration (0 and 2) indicate the bounds of the area being evaluated.

Integration Techniques

To evaluate integrals, various techniques can be employed, such as substitution, integration by parts, or polynomial expansion. For the integral ∫₀² (2𝓍 + 1)³ d𝓍, expanding the integrand (2𝓍 + 1)³ into a polynomial form can simplify the integration process, making it easier to compute the definite integral.

Fundamental Theorem of Calculus

The Fundamental Theorem of Calculus links differentiation and integration, stating that if F is an antiderivative of f on an interval [a, b], then ∫ₐᵇ f(x) dx = F(b) - F(a). This theorem allows us to evaluate definite integrals by finding an antiderivative of the integrand, which is essential for solving the given integral problem.

Evaluating integrals Evaluate the following integrals.∫₀² (2𝓍 + 1)³ d𝓍