Skip to main content
Ch. 5 - Integration
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243당신이 사용하는 게 아니라요?교과서 변경
5장, 문제 5.1.59c

Explain why or why not Determine whether the following statements are true and give an explanation or counterexample.
(c) For an increasing or decreasing nonconstant function on an interval [a,b] and a given value of n, the value of the midpoint Riemann sum always lies between the values of the left and right Riemann sums.

검증된 단계별 안내
1
Understand the problem: The question asks us to determine whether the midpoint Riemann sum for a nonconstant, increasing or decreasing function on an interval [a, b] always lies between the left and right Riemann sums. We need to analyze this statement and provide reasoning or a counterexample.
Recall the definitions: The left Riemann sum (LRS) uses the left endpoints of subintervals to approximate the integral, while the right Riemann sum (RRS) uses the right endpoints. The midpoint Riemann sum (MRS) uses the midpoints of subintervals. For an increasing function, LRS underestimates the integral, and RRS overestimates it. For a decreasing function, the opposite is true.
Analyze the behavior for an increasing function: For an increasing function, the function values at the midpoints of subintervals are greater than the left endpoints but less than the right endpoints. This suggests that the midpoint Riemann sum should lie between the left and right Riemann sums.
Analyze the behavior for a decreasing function: For a decreasing function, the function values at the midpoints of subintervals are less than the left endpoints but greater than the right endpoints. This also suggests that the midpoint Riemann sum should lie between the left and right Riemann sums.
Conclude and justify: Based on the analysis, the statement is true. For a nonconstant, increasing or decreasing function, the midpoint Riemann sum always lies between the left and right Riemann sums because the midpoint values are intermediate between the left and right endpoint values for each subinterval.

비슷한 문제에 대한 검증된 영상 답변:

이 영상 해법은 위 문제에 도움이 된다고 튜터들이 추천한 것입니다.
영상 길이:
1m
도움이 되었나요?

주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Riemann Sums

Riemann sums are a method for approximating the integral of a function over an interval by dividing the interval into subintervals and summing the areas of rectangles formed. The left Riemann sum uses the left endpoints of the subintervals, while the right Riemann sum uses the right endpoints. The midpoint Riemann sum, on the other hand, uses the midpoints of the subintervals, which can provide a more accurate approximation of the area under the curve.
추천 영상:
가이드 코스
06:11
Introduction to Riemann Sums

Monotonic Functions

A monotonic function is one that is either entirely non-increasing or non-decreasing over a given interval. For an increasing function, as the input values increase, the output values also increase, while for a decreasing function, the output values decrease. Understanding the behavior of monotonic functions is crucial when analyzing the relationships between different types of Riemann sums, as it affects the placement of the rectangles used in the approximations.
추천 영상:
가이드 코스
06:21
Properties of Functions

Comparison of Riemann Sums

When comparing Riemann sums for a monotonic function, the midpoint Riemann sum typically lies between the left and right Riemann sums. This is because the midpoint captures the average height of the function over each subinterval, while the left and right sums can overestimate or underestimate the area depending on the function's behavior. This property is particularly important in understanding the accuracy of numerical integration methods.
추천 영상:
가이드 코스
06:11
Introduction to Riemann Sums
관련 실천
교과서 질문

Sigma notation Evaluate the following expressions.                                                                                                                                          

(c)     4                                                                                                                                                                               

       ∑ κ²                                                                                                                                                                          

       κ=1                         

교과서 질문

Properties of integrals Use only the fact that ∫₀⁴ 3𝓍 (4 ―𝓍) d𝓍 = 32, and the definitions and properties of integrals, to evaluate the following integrals, if possible.


(c) ∫₄⁰ 6𝓍(4 ― 𝓍) d(𝓍)

57
views
교과서 질문

Properties of integrals Suppose ∫₀³ƒ(𝓍) d𝓍 = 2 , ∫₃⁶ƒ(𝓍) d𝓍 = ―5 , and ∫₃⁶g(𝓍) d𝓍 = 1. Evaluate the following integrals.

(c) ∫₃⁶ (3ƒ(𝓍) ― g(𝓍)) d𝓍

42
views
교과서 질문

Substitutions Suppose ƒ is an even function with ∫₀⁸ ƒ(𝓍) d𝓍 = 9 . Evaluate each integral.                                                                                                       

(b) ∫²₋₂ 𝓍²ƒ(𝓍³) d𝓍

44
views
교과서 질문

Explain why or why not Determine whether the following statements are true and give an explanation or counterexample. Assume ƒ, ƒ', and ƒ'' are continuous functions for all real numbers.                                                                                                                                                           

                                                                                                                                                                    

(c) ∫ sin 2𝓍 d𝓍 = 2 ∫ sin 𝓍 d𝓍 .

35
views
교과서 질문

Working with area functions Consider the function ƒ and the points a, b, and c.

(c) Evaluate A(b) and A(c). Interpret the results using the graphs of part (b) .

ƒ(𝓍) = ― 12𝓍 (𝓍―1) (𝓍― 2) ; a = 0 , b = 1 , c = 2

62
views