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Ch. 5 - Integration
5์žฅ, ๋ฌธ์ œ 5.R.97

Find the average value of ฦ’(๐“) = eยฒหฃ on [0, ln 2] .

๊ฒ€์ฆ๋œ ๋‹จ๊ณ„๋ณ„ ์•ˆ๋‚ด
1
Step 1: Recall the formula for the average value of a function ฦ’(๐“) on the interval [a, b], which is given by: 1(b-a)fxdx. Here, a = 0 and b = ln(2).
Step 2: Substitute the given function ฦ’(๐“) = eยฒหฃ into the formula. The integral becomes: 1(ln(2)-0)e2xdx.
Step 3: Compute the integral of eยฒหฃ with respect to ๐“. Use the rule for integrating exponential functions: ekxdx=ekxk, where k is a constant. Here, k = 2.
Step 4: Evaluate the definite integral from ๐“ = 0 to ๐“ = ln(2). Substitute the limits of integration into the antiderivative obtained in Step 3.
Step 5: Multiply the result of the definite integral by 1ln(2) to find the average value of the function on the interval [0, ln(2)].

๋น„์Šทํ•œ ๋ฌธ์ œ์— ๋Œ€ํ•œ ๊ฒ€์ฆ๋œ ์˜์ƒ ๋‹ต๋ณ€:

์ด ์˜์ƒ ํ•ด๋ฒ•์€ ์œ„ ๋ฌธ์ œ์— ๋„์›€์ด ๋œ๋‹ค๊ณ  ํŠœํ„ฐ๋“ค์ด ์ถ”์ฒœํ•œ ๊ฒƒ์ž…๋‹ˆ๋‹ค.
์˜์ƒ ๊ธธ์ด:
2m
๋„์›€์ด ๋˜์—ˆ๋‚˜์š”?

์ฃผ์š” ๊ฐœ๋…

์งˆ๋ฌธ์— ์˜ฌ๋ฐ”๋ฅด๊ฒŒ ๋‹ตํ•˜๊ธฐ ์œ„ํ•ด ๋ฐ˜๋“œ์‹œ ์ดํ•ดํ•ด์•ผ ํ•˜๋Š” ํ•ต์‹ฌ ๊ฐœ๋…๋“ค์€ ๋‹ค์Œ๊ณผ ๊ฐ™์Šต๋‹ˆ๋‹ค.

Average Value of a Function

The average value of a continuous function f(x) over the interval [a, b] is calculated using the formula (1/(b-a)) * โˆซ[a to b] f(x) dx. This concept is essential for determining how the function behaves on the specified interval, providing a single representative value that summarizes the function's output.
์ถ”์ฒœ ์˜์ƒ:

Definite Integral

A definite integral represents the accumulation of quantities, such as area under a curve, over a specific interval [a, b]. It is denoted as โˆซ[a to b] f(x) dx and is calculated using the Fundamental Theorem of Calculus, which connects differentiation and integration, allowing us to evaluate the integral using antiderivatives.
์ถ”์ฒœ ์˜์ƒ:
๊ฐ€์ด๋“œ ์ฝ”์Šค
05:43
Definition of the Definite Integral

Exponential Functions

Exponential functions, such as f(x) = e^(kx), where e is Euler's number, are characterized by their constant growth rate proportional to their value. In this case, the function e^(2x) grows rapidly as x increases, and understanding its properties is crucial for evaluating integrals involving exponential terms.
์ถ”์ฒœ ์˜์ƒ:
6:13
Exponential Functions
๊ด€๋ จ ์‹ค์ฒœ
๊ต๊ณผ์„œ ์งˆ๋ฌธ

Area of regions Compute the area of the region bounded by the graph of ฦ’ and the ๐“-axis on the given interval. You may find it useful to sketch the region.                                              

                                                                                                                                                                                    

 ฦ’(๐“) = 16โ€•๐“ยฒ on [โ€•4, 4]

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๊ต๊ณผ์„œ ์งˆ๋ฌธ

Properties of integrals Suppose โˆซโ‚โด ฦ’(๐“) d๐“ = 6 , โˆซโ‚โด g(๐“) d๐“ = 4 and โˆซโ‚ƒโด ฦ’(๐“) d๐“ = 2 . Evaluate the following integrals or state that there is not enough information.


โ€•โˆซโ‚„ยน 2ฦ’(๐“) d๐“

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๊ต๊ณผ์„œ ์งˆ๋ฌธ

Area functions and the Fundamental Theorem Consider the function

ฦ’(t) = { t      if  โ€•2 โ‰ค t < 0

tยฒ/2    if    0 โ‰ค t โ‰ค 2

and its graph shown below. Let F(๐“) = โˆซโ‚‹โ‚หฃ ฦ’(t) dt and G(๐“) = โˆซโ‚‹โ‚‚หฃ ฦ’(t) dt.

(e) Evaluate F ''(โ€•1) and F ''(1). Interpret these values.

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๊ต๊ณผ์„œ ์งˆ๋ฌธ

Area by geometry Use geometry to evaluate the following definite integrals, where the graph of ฦ’ is given in the figure.

(c) โˆซโ‚…โท ฦ’(๐“) d๐“

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๊ต๊ณผ์„œ ์งˆ๋ฌธ

Integration by Riemann sums Consider the integral โˆซโ‚โด (3๐“โ€• 2) d๐“.


(a) Evaluate the right Riemann sum for the integral with n = 3 .

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๊ต๊ณผ์„œ ์งˆ๋ฌธ

Evaluating integrals Evaluate the following integrals.                                                                                                                                         

                                                                                                                                                                    

 โˆซ ๐“โท โˆš(๐“โด + 1d๐“)

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