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Ch. 5 - Integration
5์žฅ, ๋ฌธ์ œ 5.R.102e

Function defined by an integral Let H (๐“) = โˆซโ‚€หฃ โˆš(4 โ€• tยฒ) dt, for โ€• 2 โ‰ค ๐“ โ‰ค 2.
(e) Find the value of s such that H (๐“) = sH(โ€•๐“)

๊ฒ€์ฆ๋œ ๋‹จ๊ณ„๋ณ„ ์•ˆ๋‚ด
1
Step 1: Understand the problem. The function H(๐“) is defined as an integral from 0 to ๐“ of โˆš(4 - tยฒ) dt. The goal is to find the value of s such that H(๐“) = sH(-๐“). This involves symmetry properties of the integral and the function.
Step 2: Analyze the integrand โˆš(4 - tยฒ). This function is even because โˆš(4 - tยฒ) = โˆš(4 - (-t)ยฒ). This means the integrand is symmetric about the y-axis.
Step 3: Use the property of definite integrals for even functions. For an even function f(t), โˆซโ‚€หฃ f(t) dt is equal to โˆซโ‚‹หฃโฐ f(t) dt. This symmetry will help relate H(๐“) and H(-๐“).
Step 4: Express H(-๐“) using the definition of the integral. H(-๐“) = โˆซโ‚€โปหฃ โˆš(4 - tยฒ) dt. By reversing the limits of integration, this becomes H(-๐“) = -โˆซโ‚‹หฃโฐ โˆš(4 - tยฒ) dt.
Step 5: Combine the symmetry property and the reversed integral to find the relationship between H(๐“) and H(-๐“). Use this relationship to determine the value of s such that H(๐“) = sH(-๐“).

๋น„์Šทํ•œ ๋ฌธ์ œ์— ๋Œ€ํ•œ ๊ฒ€์ฆ๋œ ์˜์ƒ ๋‹ต๋ณ€:

์ด ์˜์ƒ ํ•ด๋ฒ•์€ ์œ„ ๋ฌธ์ œ์— ๋„์›€์ด ๋œ๋‹ค๊ณ  ํŠœํ„ฐ๋“ค์ด ์ถ”์ฒœํ•œ ๊ฒƒ์ž…๋‹ˆ๋‹ค.
์˜์ƒ ๊ธธ์ด:
4m
๋„์›€์ด ๋˜์—ˆ๋‚˜์š”?

์ฃผ์š” ๊ฐœ๋…

์งˆ๋ฌธ์— ์˜ฌ๋ฐ”๋ฅด๊ฒŒ ๋‹ตํ•˜๊ธฐ ์œ„ํ•ด ๋ฐ˜๋“œ์‹œ ์ดํ•ดํ•ด์•ผ ํ•˜๋Š” ํ•ต์‹ฌ ๊ฐœ๋…๋“ค์€ ๋‹ค์Œ๊ณผ ๊ฐ™์Šต๋‹ˆ๋‹ค.

Definite Integral

A definite integral represents the signed area under a curve defined by a function over a specific interval. In this case, H(๐“) is defined as the integral of โˆš(4 - tยฒ) from 0 to ๐“, which geometrically corresponds to the area under the curve of the function from the lower limit to the upper limit.
์ถ”์ฒœ ์˜์ƒ:
05:43
Definition of the Definite Integral

Symmetry in Functions

Symmetry in functions refers to the property where a function exhibits the same behavior when its input is negated. For the function H(๐“), understanding its symmetry can help in finding the relationship between H(๐“) and H(โˆ’๐“), which is crucial for solving the equation H(๐“) = sH(โˆ’๐“).
์ถ”์ฒœ ์˜์ƒ:
06:21
Properties of Functions

Parameterization

Parameterization involves expressing a function in terms of a variable that can take on a range of values. In this context, the variable s acts as a parameter that scales the relationship between H(๐“) and H(โˆ’๐“). Finding the appropriate value of s requires analyzing how these two integrals relate to each other.
์ถ”์ฒœ ์˜์ƒ:
๊ฐ€์ด๋“œ ์ฝ”์Šค
04:26
Parameterizing Equations Example 4
๊ด€๋ จ ์‹ค์ฒœ
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