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Ch. 5 - Integration
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243당신이 사용하는 게 아니라요?교과서 변경
5장, 문제 5.2.34d

{Use of Tech} Approximating definite integrals Complete the following steps for the given integral and the given value of n. 
(d) Determine which Riemann sum (left or right) underestimates the value of the definite integral and which overestimates the value of the definite integral.


∫₀^π/2 cos 𝓍 d𝓍 ; n = 4

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Step 1: Understand the problem. The goal is to approximate the definite integral ∫₀^(π/2) cos(𝓍) d𝓍 using Riemann sums with n = 4 subintervals. Additionally, determine which Riemann sum (left or right) underestimates or overestimates the integral.
Step 2: Divide the interval [0, π/2] into n = 4 equal subintervals. The width of each subinterval, Δ𝓍, is calculated as Δ𝓍 = (b - a) / n, where a = 0 and b = π/2.
Step 3: For the left Riemann sum, use the left endpoints of each subinterval to evaluate the function cos(𝓍). The left Riemann sum is given by the formula: S_left = Δ𝓍 * Σ[f(x_i)], where x_i are the left endpoints of the subintervals.
Step 4: For the right Riemann sum, use the right endpoints of each subinterval to evaluate the function cos(𝓍). The right Riemann sum is given by the formula: S_right = Δ𝓍 * Σ[f(x_i)], where x_i are the right endpoints of the subintervals.
Step 5: Analyze the behavior of the function cos(𝓍) on the interval [0, π/2]. Since cos(𝓍) is decreasing on this interval, the left Riemann sum will overestimate the integral (as it uses higher values of the function at the left endpoints), while the right Riemann sum will underestimate the integral (as it uses lower values of the function at the right endpoints).

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주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Riemann Sums

Riemann sums are a method for approximating the value of a definite integral by dividing the area under a curve into smaller rectangles. The sum of the areas of these rectangles provides an estimate of the integral's value. Depending on whether the left or right endpoints of the subintervals are used, the Riemann sum can either overestimate or underestimate the actual area, which is crucial for understanding the behavior of the integral.
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가이드 코스
06:11
Introduction to Riemann Sums

Definite Integrals

A definite integral represents the net area under a curve between two specified limits, in this case, from 0 to π/2 for the function cos(x). It is calculated using the Fundamental Theorem of Calculus, which connects differentiation and integration. Understanding definite integrals is essential for evaluating the total accumulation of quantities, such as area, over an interval.
추천 영상:
가이드 코스
05:43
Definition of the Definite Integral

Overestimation and Underestimation

In the context of Riemann sums, overestimation occurs when the sum of the areas of the rectangles exceeds the actual area under the curve, while underestimation occurs when the sum falls short. For a decreasing function like cos(x) on the interval [0, π/2], the left Riemann sum will overestimate the integral, and the right Riemann sum will underestimate it. Recognizing these patterns is vital for accurately interpreting the results of numerical integration.
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가이드 코스
10:22
Left, Right, & Midpoint Riemann Sums Example 1
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교과서 질문

{Use of Tech} Approximating definite integrals Complete the following steps for the given integral and the given value of n. 

(d) Determine which Riemann sum (left or right) underestimates the value of the definite integral and which overestimates the value of the definite integral.


∫₃⁶ (1―2𝓍) d𝓍 ; n = 6

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교과서 질문

Use Table 5.6 to evaluate the following indefinite integrals.                                                                                                               

                                                                                                                                                                  

 (e) ∫ d𝓍/(81 + 9𝓍²) (Hint: Factor a 9 out of the denominator first.)  

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Matching functions with area functions Match the functions ƒ, whose graphs are given in a― d, with the area functions A (𝓍) = ∫₀ˣ ƒ(t) dt, whose graphs are given in A–D.



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Left and right Riemann sums Complete the following steps for the given function, interval, and value of n.

{Use of Tech} ƒ(𝓍) = e ˣ/₂ on [1,4]; n = 6

(d) Calculate the left and right Riemann sums. 

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Explain why or why not Determine whether the following statements are true and give an explanation or counterexample.

(d) If ∫ₐᵇ ƒ(𝓍) d𝓍 = ∫ₐᵇ ƒ(𝓍) d𝓍, then ƒ is a constant function. 

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Midpoint Riemann sums Complete the following steps for the given function, interval, and value of n.


ƒ(𝓍) = 1/x on [1,6] ; n = 5


(d) Calculate the midpoint Riemann sum.

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