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Ch. 6 - Applications of Integration
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243당신이 사용하는 게 아니라요?교과서 변경
6장, 문제 6.1.57b

55–58. Marginal cost Consider the following marginal cost functions.


b. Find the additional cost incurred in dollars when production is increased from 500 units to 550 units.


C′(x) = 300+10x−0.01x²

검증된 단계별 안내
1
Understand that the marginal cost function \(C\prime(x)\) represents the rate of change of the total cost with respect to the number of units produced, \(x\). To find the additional cost incurred when production increases from 500 to 550 units, we need to find the change in total cost over this interval.
Recall that the additional cost when increasing production from \(x = a\) to \(x = b\) can be found by integrating the marginal cost function over the interval \([a, b]\). In this case, we want to compute \(\int_{500}^{550} C\prime(x) \, dx\).
Set up the definite integral using the given marginal cost function: \(\int_{500}^{550} \left(300 + 10x - 0.01x^{2}\right) \, dx\).
Integrate the function term-by-term: - The integral of \(300\) with respect to \(x\) is \$300x$. - The integral of \$10x$ is \$5x^{2}$. - The integral of $-0.01x^{2}$ is \(-0.01 \times \frac{x^{3}}{3} = -\frac{0.01}{3} x^{3}\).
Evaluate the resulting antiderivative at the upper limit \(x=550\) and the lower limit \(x=500\), then subtract to find the total additional cost: \(\left[300x + 5x^{2} - \frac{0.01}{3} x^{3}\right]_{500}^{550} = \left(300 \times 550 + 5 \times 550^{2} - \frac{0.01}{3} \times 550^{3}\right) - \left(300 \times 500 + 5 \times 500^{2} - \frac{0.01}{3} \times 500^{3}\right)\).

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주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Marginal Cost Function

The marginal cost function, C′(x), represents the rate of change of the total cost with respect to the number of units produced. It indicates the additional cost of producing one more unit at production level x. Understanding this helps in estimating cost changes for small increases in production.
추천 영상:
가이드 코스
06:21
Properties of Functions

Definite Integral for Accumulated Change

To find the total additional cost when production increases over an interval, integrate the marginal cost function over that range. The definite integral of C′(x) from x = 500 to x = 550 gives the exact increase in total cost for producing those extra 50 units.
추천 영상:
가이드 코스
05:43
Definition of the Definite Integral

Evaluating Polynomial Integrals

Since the marginal cost function is a polynomial, integrating it involves applying power rules to each term. Accurate integration and evaluation at the bounds are essential to compute the total additional cost correctly, ensuring precise results for the production increase.
추천 영상:
07:00
Taylor Polynomials
관련 실천
교과서 질문

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b. What is the displacement of the object over the interval [2, 6]? 

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교과서 질문

55–58. Marginal cost Consider the following marginal cost functions.


b. Find the additional cost incurred in dollars when production is increased from 500 units to 550 units.


C′(x)=200−0.05x

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b. Find the displacement of the object on the interval 0≤t≤6.

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b. How much work is done in compressing the spring 0.5 m from its equilibrium position?

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Winding a chain A 30-m-long chain hangs vertically from a cylinder attached to a winch. Assume there is no friction in the system and the chain has a density of 5kg/m.

b. How much work is required to wind the chain onto the cylinder if a 50-kg block is attached to the end of the chain?

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교과서 질문

Blood flow A typical human heart pumps 70 mL of blood (the stroke volume) with each beat. Assuming a heart rate of 60 beats/min (1 beat/s), a reasonable model for the outflow rate of the heart is V′(t)=70(1+sin 2πt), where V(t) is the amount of blood (in milliliters) pumped over the interval [0,t],V(0)=0 and t is measured in seconds.


b. Find the function that gives the total blood pumped between t=0 and a future time t>0.

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