교과서 질문
Explain the steps required to find the length of a curve x = g(y) between y=c and y=d.
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Ch. 6 - Applications of Integration
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243
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TOC.tableOfContents
- Ch. 1 - Functions210
- Ch. 2 - Limits371
- Ch. 3 - Derivatives633
- Ch. 4 - Applications of the Derivative412
- Ch. 5 - Integration328
- Ch. 6 - Applications of Integration331
- Ch. 7 - Logarithmic, Exponential Functions, and Hyperbolic Functions177
- Ch. 8 - Integration Techniques394
- Ch. 9 - Differential Equations179
- Ch. 10 - Sequences and Infinite Series339
- Ch. 11 - Power Series218
- Ch.12 - Parametric and Polar Curves215
6장, 문제 6.4.32
9-34. Shell method Let R be the region bounded by the following curves. Use the shell method to find the volume of the solid generated when R is revolved about indicated axis.
{Use of Tech} y = √50 -2x², in the first quadrant; about the x-axis
검증된 단계별 안내1
First, identify the region R bounded by the curve \(y = \sqrt{50 - 2x^2}\) in the first quadrant. Since we are in the first quadrant, both \(x\) and \(y\) are non-negative, so \(x \geq 0\) and \(y \geq 0\).
Since the solid is generated by revolving the region about the x-axis, and we are asked to use the shell method, recall that the shell method involves integrating cylindrical shells formed by slicing the region parallel to the axis of revolution. Here, the axis of revolution is horizontal (x-axis), so we will integrate with respect to \(y\).
Express \(x\) in terms of \(y\) from the given curve: starting with \(y = \sqrt{50 - 2x^2}\), square both sides to get \(y^2 = 50 - 2x^2\), then solve for \(x^2\) to find \(x^2 = \frac{50 - y^2}{2}\), and finally \(x = \sqrt{\frac{50 - y^2}{2}}\).
Set up the shell radius and height for the shell method. The radius of a shell is the distance from the shell to the axis of revolution (x-axis), which is simply \(y\). The height of the shell is the horizontal length of the region at that \(y\) value, which is \(x = \sqrt{\frac{50 - y^2}{2}}\).
Write the volume integral using the shell method formula: \(V = \int_{y=0}^{y=\sqrt{50}} 2\pi \times (\text{radius}) \times (\text{height}) \, dy = \int_0^{\sqrt{50}} 2\pi y \cdot \sqrt{\frac{50 - y^2}{2}} \, dy\). This integral represents the volume of the solid.
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이 영상 해법은 위 문제에 도움이 된다고 튜터들이 추천한 것입니다.
영상 길이:
7m주요 개념
질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.
Shell Method for Volume
The shell method calculates the volume of a solid of revolution by integrating cylindrical shells. Each shell's volume is approximated by its circumference times height times thickness. This method is especially useful when the axis of rotation is parallel to the axis of the variable of integration.
추천 영상:
04:48
Finding Volume Using Disks
Region Bounded by Curves
Understanding the region bounded by the given curves is essential to set correct integration limits. Here, the curve y = √(50 - 2x²) in the first quadrant defines the boundary, meaning x and y are non-negative, which restricts the domain for integration.
추천 영상:
05:06Finding Area When Bounds Are Not Given
Revolution About the x-axis
Revolving a region about the x-axis means the solid is generated by rotating the area around the horizontal axis. This affects the radius and height expressions in the shell method, as shells are formed perpendicular to the axis of rotation.
추천 영상:
06:30Disk Method Using y-Axis
관련 실천
교과서 질문
Let R be the region bounded by the following curves. Find the volume of the solid generated when R is revolved about the given axis.
y=x,y=x+2,x=0, and x=4 ; about the x-axis
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46–50. Force on dams The following figures show the shapes and dimensions of small dams. Assuming the water level is at the top of the dam, find the total force on the face of the dam.
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y=(3x)^1/3 , for 0≤x≤8/3; about the y-axis
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교과서 질문
39–44. Shell method about other lines Let R be the region bounded by y = x²,x=1, and y=0. Use the shell method to find the volume of the solid generated when R is revolved about the following lines.
y = 2
46
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교과서 질문
39–44. Shell method about other lines Let R be the region bounded by y = x²,x=1, and y=0. Use the shell method to find the volume of the solid generated when R is revolved about the following lines.
y = -2
49
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