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Ch. 6 - Applications of Integration
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243당신이 사용하는 게 아니라요?교과서 변경
6장, 문제 6.5.35b

Functions from arc length What differentiable functions have an arc length on the interval [a, b] given by the following integrals? Note that the answers are not unique. Give a family of functions that satisfy the conditions.
b. ∫a^b √1+36 cos² 2xdx

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Recall the formula for the arc length of a differentiable function \( y = f(x) \) on the interval \([a,b]\): \[ L = \int_a^b \sqrt{1 + \left(\frac{dy}{dx}\right)^2} \, dx \]
Compare the given integral for arc length: \[ \int_a^b \sqrt{1 + 36 \cos^2(2x)} \, dx \] with the general formula. This means: \[ 1 + \left(\frac{dy}{dx}\right)^2 = 1 + 36 \cos^2(2x) \]
From the equality above, isolate \( \frac{dy}{dx} \): \[ \left(\frac{dy}{dx}\right)^2 = 36 \cos^2(2x) \] which implies \[ \frac{dy}{dx} = \pm 6 \cos(2x) \]
Integrate \( \frac{dy}{dx} = \pm 6 \cos(2x) \) with respect to \( x \) to find the family of functions: \[ y = \pm 6 \int \cos(2x) \, dx + C \]
Recall that \( \int \cos(2x) \, dx = \frac{1}{2} \sin(2x) + C \), so the family of functions is: \[ y = \pm 3 \sin(2x) + C \] where \( C \) is an arbitrary constant.

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주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Arc Length Formula

The arc length of a differentiable function y = f(x) on [a, b] is given by the integral ∫_a^b √(1 + (f'(x))²) dx. This formula measures the length of the curve by summing infinitesimal line segments, where the integrand involves the derivative of the function.
추천 영상:
가이드 코스
06:29
Arc Length of Parametric Curves

Relating the Integrand to the Derivative

To find functions with a given arc length integral, identify the expression inside the square root as 1 + (f'(x))². Equate this to the given integrand to solve for f'(x), which helps determine the family of functions whose derivatives satisfy the condition.
추천 영상:
가이드 코스
04:16
Intro To Related Rates

Solving Differential Equations for Families of Functions

Once f'(x) is found, integrate it to obtain the general form of f(x). Since integration introduces an arbitrary constant, the solution represents a family of functions, not a unique one, matching the problem's requirement for multiple solutions.
추천 영상:
06:06
Solving Separable Differential Equations
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