Spring work

b. It takes 50 N of force to stretch a spring 0.2 m from its equilibrium position. How much work is needed to stretch it an additional 0.5 m?

검증된 단계별 안내

Identify the spring constant \( k \) using Hooke's Law, which states that the force \( F \) required to stretch or compress a spring by a distance \( x \) is \( F = kx \). Given \( F = 50 \) N and \( x = 0.2 \) m, solve for \( k \) by rearranging the formula to \( k = \frac{F}{x} \).

Express the work done to stretch a spring from position \( x = a \) to \( x = b \) using the integral formula for work: \( W = \int_a^b F(x) \, dx \), where \( F(x) = kx \) is the force at position \( x \).

Set the limits of integration to represent the additional stretch: since the spring is already stretched 0.2 m, the work needed to stretch it an additional 0.5 m corresponds to stretching from \( x = 0.2 \) m to \( x = 0.7 \) m (because \( 0.2 + 0.5 = 0.7 \)).

Write the integral for the work done as \( W = \int_{0.2}^{0.7} kx \, dx \). Substitute the value of \( k \) found in step 1 into this integral.

Evaluate the integral \( \int_{0.2}^{0.7} kx \, dx = k \int_{0.2}^{0.7} x \, dx = k \left[ \frac{x^2}{2} \right]_{0.2}^{0.7} \) to find the work done in stretching the spring the additional 0.5 m.

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주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Hooke's Law

Hooke's Law states that the force required to stretch or compress a spring is proportional to the displacement from its equilibrium position, expressed as F = kx, where k is the spring constant and x is the displacement. This law helps determine the spring constant from the given force and displacement.

Work Done by a Variable Force

When stretching a spring, the force varies with displacement, so work done is calculated by integrating the force over the distance stretched. The work done to stretch a spring from x = a to x = b is W = (1/2)k(b² - a²), reflecting the area under the force-displacement curve.

Spring Constant Calculation

The spring constant k quantifies the stiffness of the spring and is found by rearranging Hooke's Law: k = F/x. Knowing k allows calculation of work done for any displacement, making it essential to first find k using the initial force and displacement before solving for additional work.

Spring workb. It takes 50 N of force to stretch a spring 0.2 m from its equilibrium position. How much work is needed to stretch it an additional 0.5 m?