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Ch. 7 - Logarithmic, Exponential Functions, and Hyperbolic Functions
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243당신이 사용하는 게 아니라요?교과서 변경
7장, 문제 7.3.41

37–56. Integrals Evaluate each integral.
∫ tanh²x dx (Hint: Use an identity.)

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Recall the identity for hyperbolic tangent squared: \(\tanh^{2}x = 1 - \sech^{2}x\). This will help simplify the integral.
Rewrite the integral using the identity: \(\int \tanh^{2}x \, dx = \int (1 - \sech^{2}x) \, dx\).
Split the integral into two separate integrals: \(\int 1 \, dx - \int \sech^{2}x \, dx\).
Integrate each term separately: The integral of 1 with respect to \(x\) is \(x\), and the integral of \(\sech^{2}x\) is \(\tanh x\).
Combine the results to write the integral as \(x - \tanh x + C\), where \(C\) is the constant of integration.

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주요 개념

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Hyperbolic Functions and Their Identities

Hyperbolic functions like tanh(x) are analogs of trigonometric functions but based on exponential functions. Key identities, such as tanh²x + sech²x = 1, help simplify expressions and integrals involving these functions.
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Using algebraic or trigonometric/hyperbolic identities can transform complicated integrals into simpler forms. For example, rewriting tanh²x using an identity allows the integral to be expressed in terms of easier-to-integrate functions.
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Basic Integration of Hyperbolic Functions

Integrals involving hyperbolic functions often reduce to standard forms, such as ∫sech²x dx = tanh x + C. Recognizing these standard integrals is essential for solving problems efficiently.
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