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Ch. 7 - Logarithmic, Exponential Functions, and Hyperbolic Functions
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243당신이 사용하는 게 아니라요?교과서 변경
7장, 문제 7.3.79a

Evaluating hyperbolic functions Evaluate each expression without using a calculator or state that the value does not exist. Simplify answers as much as possible.


a. cosh 0

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1
Recall the definition of the hyperbolic cosine function: \(\cosh x = \frac{e^{x} + e^{-x}}{2}\).
Substitute \(x = 0\) into the definition: \(\cosh 0 = \frac{e^{0} + e^{-0}}{2}\).
Evaluate the exponentials: \(e^{0} = 1\) and \(e^{-0} = 1\).
Add the values in the numerator: \(1 + 1 = 2\).
Divide by 2 to simplify: \(\cosh 0 = \frac{2}{2}\).

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2m
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주요 개념

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Definition of Hyperbolic Cosine (cosh)

The hyperbolic cosine function, cosh(x), is defined as (e^x + e^(-x)) / 2. It is an even function and describes the shape of a hanging cable or chain (catenary). Understanding this definition allows direct evaluation of cosh at any point, including zero.
추천 영상:
05:43
Definition of the Definite Integral

Properties of Exponential Functions

Exponential functions e^x and e^(-x) are fundamental in defining hyperbolic functions. Knowing that e^0 = 1 simplifies calculations, especially when evaluating cosh(0), since it involves e^0 and e^(-0). This property helps in simplifying expressions without a calculator.
추천 영상:
06:21
Properties of Functions

Evaluating Functions at Specific Points

Evaluating a function at a specific point means substituting the value into the function's formula and simplifying. For cosh(0), substituting x=0 into the definition and simplifying using known values of exponentials yields the exact result without approximation.
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4:26
Evaluating Composed Functions
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a. Find an exponential decay function V₁(t) that equals the total volume of the quiescent cells in the tumor t days after treatment.

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a. Are there numbers 0 < a < 1 such that ∫₁₋ₐ¹⁺ᵃ f(x) dx = 0?

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a. Based on these figures, find an exponential growth function for the power (rate of electricity use) for the city.

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Terminal velocity Refer to Exercises 95 and 96.


a. Compute a jumper’s terminal velocity, which is defined as lim t → ∞ v(t) = lim t → ∞ √(mg/k) tanh (√(kg/m) t).

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Falling body When an object falling from rest encounters air resistance proportional to the square of its velocity, the distance it falls (in meters) after t seconds is given by d(t) = (m/k) ln (cosh (√(kg/m) t)), where m is the mass of the object in kilograms, g = 9.8 m/s² is the acceleration due to gravity, and k is a physical constant.


a. A BASE jumper (m = 75 kg) leaps from a tall cliff and performs a ten-second delay (she free-falls for 10 s and then opens her chute). How far does she fall in 10 s? Assume k = 0.2.

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