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Ch. 8 - Integration Techniques
Briggs - Calculus: Early Transcendentals 3rd Edition
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8장, 문제 8.9.16

7–58. Improper integrals Evaluate the following integrals or state that they diverge.
16. ∫ (from -∞ to ∞) (1/(x² + a²)) dx, a > 0

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Recognize that the integral is an improper integral over the entire real line from \(-\infty\) to \(\infty\) of the function \(\frac{1}{x^{2} + a^{2}}\), where \(a > 0\).
Since the integral is over an infinite interval, rewrite it as a limit: \(\displaystyle \int_{-\infty}^{\infty} \frac{1}{x^{2} + a^{2}} \, dx = \lim_{R \to \infty} \int_{-R}^{R} \frac{1}{x^{2} + a^{2}} \, dx\).
Use the fact that the integrand is an even function, meaning \(f(-x) = f(x)\), so the integral from \(-R\) to \(R\) can be expressed as twice the integral from \(0\) to \(R\): \(\int_{-R}^{R} \frac{1}{x^{2} + a^{2}} \, dx = 2 \int_{0}^{R} \frac{1}{x^{2} + a^{2}} \, dx\).
Recall the antiderivative formula: \(\int \frac{1}{x^{2} + a^{2}} \, dx = \frac{1}{a} \arctan\left( \frac{x}{a} \right) + C\). Use this to evaluate the definite integral from \(0\) to \(R\).
Substitute the limits into the antiderivative, multiply by 2, and then take the limit as \(R \to \infty\) to determine whether the integral converges or diverges.

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주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Improper Integrals

Improper integrals involve integration over infinite intervals or integrands with infinite discontinuities. To evaluate them, limits are used to approach the problematic points, determining if the integral converges to a finite value or diverges.
추천 영상:
11:11
Improper Integrals: Infinite Intervals

Integration of Rational Functions

Rational functions are ratios of polynomials. Integrals of the form 1/(x² + a²) are standard and often solved using inverse trigonometric functions, specifically the arctangent, which helps in finding antiderivatives for such expressions.
추천 영상:
6:04
Intro to Rational Functions

Convergence of Integrals over Infinite Limits

When integrating over infinite limits, it is essential to check if the integral converges by evaluating the limit of the integral as the bounds approach infinity. For functions like 1/(x² + a²), the integral converges due to the function's decay rate.
추천 영상:
11:11
Improper Integrals: Infinite Intervals