Skip to main content
Ch. 8 - Integration Techniques
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243당신이 사용하는 게 아니라요?교과서 변경
8장, 문제 8.1.16

7–64. Integration review Evaluate the following integrals.
16. ∫ from 0 to 1 of (t² / (1 + t⁶)) dt

검증된 단계별 안내
1
Step 1: Recognize that the integral ∫ from 0 to 1 of (t² / (1 + t⁶)) dt involves a rational function. Look for substitution techniques to simplify the integrand.
Step 2: Let u = 1 + t⁶. Then, compute the derivative of u with respect to t: du/dt = 6t⁵. Rearrange to express dt in terms of du: dt = du / (6t⁵).
Step 3: Substitute u and dt into the integral. Replace t² using the substitution u = 1 + t⁶, which implies t² = (u - 1)^(1/3). The integral becomes ∫ (u - 1)^(1/3) / (6t⁵ * u) du.
Step 4: Simplify the expression further by substituting t⁵ in terms of u. From u = 1 + t⁶, t⁵ = ((u - 1)^(5/6)). Replace t⁵ in the denominator and simplify the integrand.
Step 5: Evaluate the resulting integral with respect to u over the transformed limits (from u = 1 to u = 2). Use standard integration techniques or numerical methods if necessary.

비슷한 문제에 대한 검증된 영상 답변:

이 영상 해법은 위 문제에 도움이 된다고 튜터들이 추천한 것입니다.
영상 길이:
2m
도움이 되었나요?

주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Definite Integrals

A definite integral calculates the accumulation of a quantity, represented as the area under a curve, between two specified limits. In this case, the integral from 0 to 1 of the function t² / (1 + t⁶) indicates that we are interested in the total area under the curve of this function from t = 0 to t = 1.
추천 영상:
가이드 코스
05:43
Definition of the Definite Integral

Integration Techniques

To evaluate integrals, various techniques can be employed, such as substitution, integration by parts, or recognizing standard forms. For the integral ∫ (t² / (1 + t⁶)) dt, one might consider substitution to simplify the integrand, making it easier to compute the area under the curve.
추천 영상:
가이드 코스
06:18
Integration by Parts for Definite Integrals

Continuous Functions

The function being integrated, t² / (1 + t⁶), is continuous over the interval [0, 1]. Continuous functions are essential in calculus because they ensure that the definite integral can be computed without any breaks or discontinuities, allowing for the application of the Fundamental Theorem of Calculus.
추천 영상:
05:34
Intro to Continuity