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Ch. 8 - Integration Techniques
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243당신이 사용하는 게 아니라요?교과서 변경
8장, 문제 8.9.74

77–86. Comparison Test Determine whether the following integrals converge or diverge.
84. ∫(from 1 to ∞) (2 + cos x) / x² dx

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Identify the integral to analyze: \(\int_{1}^{\infty} \frac{2 + \cos x}{x^{2}} \, dx\) and note that it is an improper integral because the upper limit is infinity.
Recall the Comparison Test for improper integrals: if \(0 \leq f(x) \leq g(x)\) for all \(x\) in \([1, \infty)\) and \(\int_{1}^{\infty} g(x) \, dx\) converges, then \(\int_{1}^{\infty} f(x) \, dx\) also converges.
Find a suitable function \(g(x)\) to compare with \(f(x) = \frac{2 + \cos x}{x^{2}}\). Since \(\cos x\) oscillates between \(-1\) and \(1\), the numerator \(2 + \cos x\) is bounded between \(1\) and \(3\). Therefore, \(\frac{2 + \cos x}{x^{2}} \leq \frac{3}{x^{2}}\) for all \(x \geq 1\).
Check the convergence of the comparison integral \(\int_{1}^{\infty} \frac{3}{x^{2}} \, dx\). Since \(\int_{1}^{\infty} \frac{1}{x^{2}} \, dx\) converges (p-integral with \(p=2 > 1\)), multiplying by a constant 3 does not affect convergence.
Conclude by the Comparison Test that since \(\int_{1}^{\infty} \frac{3}{x^{2}} \, dx\) converges and \(\frac{2 + \cos x}{x^{2}} \leq \frac{3}{x^{2}}\), the original integral \(\int_{1}^{\infty} \frac{2 + \cos x}{x^{2}} \, dx\) also converges.

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주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Improper Integrals

Improper integrals involve integration over an infinite interval or where the integrand has an infinite discontinuity. To evaluate convergence, we consider the limit of the integral as the upper bound approaches infinity. Understanding this concept is essential for determining whether the integral converges or diverges.
추천 영상:
11:11
Improper Integrals: Infinite Intervals

Comparison Test for Improper Integrals

The Comparison Test helps determine convergence by comparing the given integral to a simpler integral with known behavior. If the integrand is less than or equal to a function whose integral converges, then the original integral also converges. Conversely, if it is greater than or equal to a divergent integral, it diverges.
추천 영상:
11:11
Improper Integrals: Infinite Intervals

Behavior of Trigonometric Functions in Integrals

Trigonometric functions like cosine oscillate but remain bounded between -1 and 1. When combined with a decaying function such as 1/x², their oscillations do not affect convergence significantly. Recognizing this helps simplify the integral by focusing on the dominant term for convergence analysis.
추천 영상:
6:04
Introduction to Trigonometric Functions