Skip to main content
Ch. 8 - Integration Techniques
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243당신이 사용하는 게 아니라요?교과서 변경
8장, 문제 8.6.38

7–84. Evaluate the following integrals.
38. ∫ from π/6 to π/2 [cos x · ln(sin x)] dx

검증된 단계별 안내
1
Step 1: Recognize that the integral involves a product of functions, specifically cos(x) and ln(sin(x)). This suggests that substitution might simplify the problem. Identify a substitution that simplifies the integral.
Step 2: Let u = sin(x). Then, compute the derivative of u with respect to x: du = cos(x) dx. This substitution transforms the integral into terms of u.
Step 3: Change the limits of integration to match the substitution. When x = π/6, u = sin(π/6) = 1/2. When x = π/2, u = sin(π/2) = 1. The new limits of integration are from u = 1/2 to u = 1.
Step 4: Rewrite the integral in terms of u using the substitution. The integral becomes ∫ from 1/2 to 1 [ln(u)] du.
Step 5: Evaluate the integral ∫ ln(u) du using integration by parts. Recall the formula for integration by parts: ∫ v dw = v*w - ∫ w dv. Let v = ln(u) and dw = du, then proceed to solve.

비슷한 문제에 대한 검증된 영상 답변:

이 영상 해법은 위 문제에 도움이 된다고 튜터들이 추천한 것입니다.
영상 길이:
7m
도움이 되었나요?

주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Definite Integrals

A definite integral calculates the accumulation of a function's values over a specific interval, represented as ∫ from a to b f(x) dx. It provides the net area under the curve of the function f(x) between the limits a and b. The Fundamental Theorem of Calculus connects differentiation and integration, allowing us to evaluate definite integrals using antiderivatives.
추천 영상:
05:43
Definition of the Definite Integral

Integration by Parts

Integration by parts is a technique used to integrate products of functions, based on the formula ∫ u dv = uv - ∫ v du. Here, u and dv are chosen parts of the integrand, where u is typically a function that simplifies upon differentiation, and dv is a function that can be easily integrated. This method is particularly useful when dealing with products of logarithmic and trigonometric functions, as seen in the given integral.
추천 영상:
06:18
Integration by Parts for Definite Integrals

Logarithmic and Trigonometric Functions

Logarithmic functions, such as ln(x), and trigonometric functions, like sin(x) and cos(x), are fundamental in calculus. The integral in question involves the product of cos(x) and ln(sin(x)), which requires understanding their properties and behaviors. Recognizing how these functions interact, especially within the limits of integration, is crucial for evaluating the integral accurately.
추천 영상:
6:04
Introduction to Trigonometric Functions