82-88. Improper integrals Evaluate the following integrals or show that the integral diverges.
82. ∫ (from -∞ to -1) dx/(x - 1)⁴

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Identify the type of improper integral: Since the integral has a lower limit of -\(\infty\), this is an improper integral with an infinite limit of integration.

Rewrite the integral as a limit: Express the integral from -\(\infty\) to -1 as \( \lim_{t \to -\infty} \int_{t}^{-1} \frac{1}{(x - 1)^4} \, dx \).

Find the antiderivative: To integrate \( \frac{1}{(x - 1)^4} \), rewrite it as \( (x - 1)^{-4} \) and use the power rule for integration, which states \( \int x^n \, dx = \frac{x^{n+1}}{n+1} + C \) for \( n \neq -1 \).

Evaluate the definite integral: Substitute the antiderivative back into the limit expression and evaluate it at the bounds \( t \) and \( -1 \).

Take the limit as \( t \to -\infty \): Analyze the behavior of the antiderivative as \( t \) approaches negative infinity to determine if the integral converges or diverges.

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Improper Integrals

Improper integrals involve integration over an infinite interval or integrands with infinite discontinuities. To evaluate them, limits are used to approach the problematic points, determining if the integral converges to a finite value or diverges.

Behavior of Rational Functions Near Singularities

Rational functions like 1/(x - a)^n can have vertical asymptotes at x = a. Understanding how the function behaves near these singularities helps determine if the integral converges or diverges, especially when the exponent n affects the rate of growth or decay.

Limit Comparison and Convergence Tests

To decide if an improper integral converges, comparison tests or limit comparison tests are used by comparing the integrand to a simpler function with known integral behavior. This method helps establish convergence or divergence without explicit integration.

82-88. Improper integrals Evaluate the following integrals or show that the integral diverges.82. ∫ (from -∞ to -1) dx/(x - 1)⁴