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Ch. 8 - Integration Techniques
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243당신이 사용하는 게 아니라요?교과서 변경
모든 교과서Briggs 3rd EditionCh. 8 - Integration Techniques문제 8.9.88b
8장, 문제 8.9.88b

88. Incorrect Calculation
b. Evaluate ∫(from -1 to 1) dx/x or show that the integral does not exist.

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1
Identify the integral to evaluate: \(\int_{-1}^{1} \frac{dx}{x}\). Notice that the integrand \(\frac{1}{x}\) is undefined at \(x=0\), which lies within the interval of integration.
Since the function is not defined at \(x=0\), split the integral into two improper integrals at the point of discontinuity: \(\int_{-1}^{1} \frac{dx}{x} = \int_{-1}^{0} \frac{dx}{x} + \int_{0}^{1} \frac{dx}{x}\).
Rewrite each integral as a limit to handle the improper nature: \(\int_{-1}^{0} \frac{dx}{x} = \lim_{t \to 0^-} \int_{-1}^{t} \frac{dx}{x}\) and \(\int_{0}^{1} \frac{dx}{x} = \lim_{s \to 0^+} \int_{s}^{1} \frac{dx}{x}\).
Evaluate the antiderivative of \(\frac{1}{x}\), which is \(\ln|x|\), and apply it to each integral before taking the limits.
Examine the behavior of the limits as \(t \to 0^-\) and \(s \to 0^+\) to determine if the integrals converge or diverge. If either limit diverges, conclude that the original integral does not exist.

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주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Improper Integrals

An improper integral occurs when the integrand is undefined or unbounded within the interval of integration. In this problem, the function 1/x is undefined at x = 0, which lies between -1 and 1, making the integral improper and requiring special evaluation methods.
추천 영상:
가이드 코스
11:11
Improper Integrals: Infinite Intervals

Cauchy Principal Value

The Cauchy principal value is a method to assign a finite value to certain improper integrals that are otherwise divergent. For ∫ from -1 to 1 of 1/x dx, the principal value considers symmetric limits approaching zero from both sides, potentially yielding a finite result despite the singularity.
추천 영상:
가이드 코스
06:37
Average Value of a Function

Non-Existence of the Integral

If the limits of the integral do not converge to a finite number due to the singularity, the integral is said not to exist in the usual sense. Since 1/x has an infinite discontinuity at zero, the integral from -1 to 1 diverges unless interpreted as a principal value.
추천 영상:
03:07
Cases Where Limits Do Not Exist
관련 실천
교과서 질문

58. Two Methods Evaluate ∫(from 0 to π/3) sin(x) · ln(cos(x)) dx in the following two ways:

b. Use substitution.

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교과서 질문

Let L(c) be the length of the parabola f(x) = x² from x = 0 to x = c, where c ≥ 0 is a constant.

b. Is L concave up or concave down on [0, ∞)?

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교과서 질문

The Eiffel Tower Property Let R be the region between the curves y = e^(-c·x) and y = -e^(-c·x) on the interval [a, ∞), where a ≥ 0 and c > 0.

The center of mass of R is located at (x̄, 0), where x̄ = [∫(a to ∞) x·e^(-c·x) dx] / [∫(a to ∞) e^(-c·x) dx]

(The profile of the Eiffel Tower is modeled by these two exponential curves; see the Guided Project ""The exponential Eiffel Tower"")

b. With a = 0 and c = 2, find the equations of the lines tangent to both curves at x = 0

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교과서 질문

Computing areas On the interval [0,2], the graphs of f(x)=x²/3 and g(x)=x²(9−x²)^(-1/2) have similar shapes.

b. Find the area of the region bounded by the graph of g and the x-axis on the interval [0,2].

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교과서 질문

{Use of Tech} Powers of sine and cosine It can be shown that

∫ from 0 to π/2 of sinⁿx dx = ∫ from 0 to π/2 of cosⁿx dx =

{

[1·3·5···(n-1)]/[2·4·6···n] · π/2 if n ≥ 2 is even

[2·4·6···(n-1)]/[3·5···n] if n ≥ 3 is odd

}

b. Evaluate the integrals with n = 10 and confirm the result.

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교과서 질문

59. Two Methods

b. Evaluate ∫(x / √(x + 1)) dx using substitution.

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