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Ch. 9 - Differential Equations
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243당신이 사용하는 게 아니라요?교과서 변경
9장, 문제 9.R.12

11–18. Solving initial value problems Use the method of your choice to find the solution of the following initial value problems.
y′(t) = -3y + 9, y(0) = 4

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1
Identify the type of differential equation given: \( y'(t) = -3y + 9 \) is a first-order linear ordinary differential equation.
Rewrite the equation in standard linear form: \( y' + 3y = 9 \). This helps us recognize the integrating factor method.
Calculate the integrating factor \( \mu(t) \) using the formula \( \mu(t) = e^{\int P(t) dt} \), where \( P(t) = 3 \). So, \( \mu(t) = e^{3t} \).
Multiply both sides of the differential equation by the integrating factor \( e^{3t} \) to get \( e^{3t} y' + 3 e^{3t} y = 9 e^{3t} \). Notice the left side is the derivative of \( e^{3t} y \).
Integrate both sides with respect to \( t \): \( \int \frac{d}{dt} (e^{3t} y) dt = \int 9 e^{3t} dt \). Then solve for \( y(t) \) and apply the initial condition \( y(0) = 4 \) to find the constant of integration.

비슷한 문제에 대한 검증된 영상 답변:

이 영상 해법은 위 문제에 도움이 된다고 튜터들이 추천한 것입니다.
영상 길이:
3m
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주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

First-Order Linear Differential Equations

These are differential equations involving the first derivative of a function and the function itself, typically in the form y' + p(t)y = q(t). Solving them often involves finding an integrating factor or using other methods to obtain the general solution.
추천 영상:
07:39
Classifying Differential Equations

Initial Value Problems (IVPs)

An IVP specifies the value of the unknown function at a particular point, such as y(0) = 4. This condition allows us to find a unique solution to the differential equation by determining the constant of integration.
추천 영상:
05:03
Initial Value Problems

Method of Integrating Factor

This technique solves linear differential equations by multiplying both sides by an integrating factor, usually e^(∫p(t)dt), which simplifies the equation into an exact derivative. Integrating then yields the solution.
추천 영상:
07:33
Euler's Method