Skip to main content
Ch.12 - Parametric and Polar Curves
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243당신이 사용하는 게 아니라요?교과서 변경
12장, 문제 12.2.111

Cartesian lemniscate Find the equation in Cartesian coordinates of the lemniscate r² = a² cos 2θ, where a is a real number.

검증된 단계별 안내
1
Recall that the given lemniscate is expressed in polar coordinates as \(r^{2} = a^{2} \cos 2\theta\), where \(r\) is the radius and \(\theta\) is the angle.
Use the double-angle identity for cosine: \(\cos 2\theta = \cos^{2} \theta - \sin^{2} \theta\).
Express \(r\), \(\cos \theta\), and \(\sin \theta\) in terms of Cartesian coordinates: \(r = \sqrt{x^{2} + y^{2}}\), \(\cos \theta = \frac{x}{r}\), and \(\sin \theta = \frac{y}{r}\).
Substitute these into the equation: \(r^{2} = a^{2} \left( \frac{x^{2}}{r^{2}} - \frac{y^{2}}{r^{2}} \right)\), which simplifies to \(r^{2} = a^{2} \frac{x^{2} - y^{2}}{r^{2}}\).
Multiply both sides by \(r^{2}\) to eliminate the denominator, resulting in \(r^{4} = a^{2} (x^{2} - y^{2})\), and then replace \(r^{2}\) by \(x^{2} + y^{2}\) to get the Cartesian form: \((x^{2} + y^{2})^{2} = a^{2} (x^{2} - y^{2})\).

비슷한 문제에 대한 검증된 영상 답변:

이 영상 해법은 위 문제에 도움이 된다고 튜터들이 추천한 것입니다.
영상 길이:
2m
도움이 되었나요?

주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Polar to Cartesian Coordinate Conversion

Polar coordinates (r, θ) relate to Cartesian coordinates (x, y) through the formulas x = r cos θ and y = r sin θ. Understanding this conversion is essential to rewrite equations given in polar form into Cartesian form by expressing r and θ in terms of x and y.
추천 영상:
05:32
Intro to Polar Coordinates

Double-Angle Trigonometric Identities

The double-angle identity for cosine, cos 2θ = cos² θ - sin² θ, helps express trigonometric functions of 2θ in terms of sin θ and cos θ. This identity is crucial for manipulating the given polar equation to relate it to x and y coordinates.
추천 영상:
4:42
Solve Trig Equations Using Identity Substitutions

Equation Manipulation and Substitution

After converting r and θ to x and y, algebraic manipulation and substitution are needed to eliminate θ and express the equation purely in terms of x and y. This process involves squaring, factoring, and rearranging terms to achieve the Cartesian form of the lemniscate.
추천 영상:
04:27
Substitution With an Extra Variable