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Ch. 10 - Infinite Sequences and Series
Hass - Thomas' Calculus 15th Edition
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10장, 문제 10.4.54

Determining Convergence or Divergence
Which of the series in Exercises 17–56 converge, and which diverge? Use any method, and give reasons for your answers.
∑ (from n=1 to ∞) 1 / (1 + 2² + 3² + ⋯ + n²)

검증된 단계별 안내
1
First, recognize the general term of the series: \( a_n = \frac{1}{1^2 + 2^2 + 3^2 + \cdots + n^2} \).
Recall the formula for the sum of the first \( n \) squares: \( 1^2 + 2^2 + \cdots + n^2 = \frac{n(n+1)(2n+1)}{6} \). Substitute this into the term to get \( a_n = \frac{1}{\frac{n(n+1)(2n+1)}{6}} = \frac{6}{n(n+1)(2n+1)} \).
Analyze the behavior of \( a_n \) for large \( n \). Since \( n(n+1)(2n+1) \) is a cubic polynomial in \( n \), \( a_n \) behaves roughly like \( \frac{6}{2n^3} = \frac{3}{n^3} \) as \( n \to \infty \).
Compare the series \( \sum a_n \) to the p-series \( \sum \frac{1}{n^p} \) with \( p = 3 \). Since \( p > 1 \), the p-series converges.
By the Comparison Test, since \( a_n \) behaves like \( \frac{3}{n^3} \) and \( \sum \frac{1}{n^3} \) converges, the original series \( \sum_{n=1}^\infty \frac{1}{1^2 + 2^2 + \cdots + n^2} \) also converges.

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주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Infinite Series and Convergence

An infinite series is the sum of infinitely many terms. Determining whether such a series converges means checking if the sum approaches a finite limit as the number of terms grows indefinitely. If the sum does not approach a finite value, the series diverges.
추천 영상:
가이드 코스
06:52
Convergence of an Infinite Series

Sum of Squares Formula

The sum of the first n squares is given by the formula 1² + 2² + ⋯ + n² = n(n + 1)(2n + 1)/6. This formula helps simplify the denominator in the given series, making it easier to analyze the behavior of the terms as n becomes large.
추천 영상:
가이드 코스
06:11
Introduction to Riemann Sums

Comparison Test for Series

The comparison test involves comparing the terms of a given series to those of a known benchmark series. If the terms of the given series are smaller than those of a convergent series, it also converges; if larger than those of a divergent series, it diverges. This test helps determine convergence without finding the exact sum.
추천 영상:
가이드 코스
09:25
Direct Comparison Test