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Ch. 10 - Infinite Sequences and Series
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077당신이 사용하는 게 아니라요?교과서 변경
10장, 문제 10.8.37

In Exercises 35–40, find the first three nonzero terms of the Maclaurin series for each function.
f(x) = (sin x) ln(1 + x)

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Recall that the Maclaurin series is the Taylor series expansion of a function about \(x = 0\). We want to find the first three nonzero terms of the Maclaurin series for \(f(x) = (\sin x) \ln(1 + x)\).
Write down the Maclaurin series expansions for each component function separately: \(\sin x = \sum_{n=0}^\infty (-1)^n \frac{x^{2n+1}}{(2n+1)!} = x - \frac{x^3}{3!} + \frac{x^5}{5!} - \cdots\) and \(\ln(1+x) = \sum_{n=1}^\infty (-1)^{n+1} \frac{x^n}{n} = x - \frac{x^2}{2} + \frac{x^3}{3} - \cdots\).
Multiply the two series together term-by-term, keeping track of powers of \(x\). Specifically, multiply each term of \(\sin x\) by each term of \(\ln(1+x)\) and combine like powers of \(x\).
Identify and collect the first three nonzero terms from the resulting series after multiplication. This involves adding coefficients of like powers of \(x\) and ignoring terms that are zero.
Write the resulting expression as the sum of these first three nonzero terms, which will be the beginning of the Maclaurin series for \(f(x) = (\sin x) \ln(1 + x)\).

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