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Ch. 2 - Limits and Continuity
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077당신이 사용하는 게 아니라요?교과서 변경
2장, 문제 2.46

Limits and Infinity


Find the limits in Exercises 37–46.


x²/³ + x⁻¹
lim --------------------
x→∞ x²/³ + cos²x

검증된 단계별 안내
1
First, identify the dominant terms in the numerator and the denominator as x approaches infinity. In this case, the dominant term in both the numerator and the denominator is x^(2/3).
Rewrite the expression by factoring out x^(2/3) from both the numerator and the denominator. This will help simplify the limit. The expression becomes: (x^(2/3) * (1 + x^(-5/3))) / (x^(2/3) * (1 + cos^2(x)/x^(2/3))).
Cancel out the common factor of x^(2/3) from the numerator and the denominator. This simplifies the expression to: (1 + x^(-5/3)) / (1 + cos^2(x)/x^(2/3)).
Evaluate the limit of each term as x approaches infinity. The term x^(-5/3) approaches 0, and cos^2(x)/x^(2/3) also approaches 0 because cos^2(x) is bounded between 0 and 1.
Substitute these limits into the simplified expression: (1 + 0) / (1 + 0) = 1. Therefore, the limit of the original expression as x approaches infinity is 1.

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주요 개념

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