Find the derivatives of the functions in Exercises 1–42.

𝔂 = 1 x² csc 2
2 x

검증된 단계별 안내

Step 1: Identify the function components. The given function is \( y = \frac{1}{x^2} \csc(2x) \). This is a product of two functions: \( u(x) = \frac{1}{x^2} \) and \( v(x) = \csc(2x) \).

Step 2: Apply the product rule for differentiation. The product rule states that if \( y = u(x) \cdot v(x) \), then \( y' = u'(x) \cdot v(x) + u(x) \cdot v'(x) \).

Step 3: Differentiate \( u(x) = \frac{1}{x^2} \). Use the power rule: \( u'(x) = -2x^{-3} \).

Step 4: Differentiate \( v(x) = \csc(2x) \). Use the chain rule: \( v'(x) = -2 \csc(2x) \cot(2x) \).

Step 5: Substitute \( u'(x) \), \( v(x) \), \( u(x) \), and \( v'(x) \) into the product rule formula to find \( y' \).

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주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Derivatives

The derivative of a function measures how the function's output value changes as its input value changes. It is a fundamental concept in calculus, representing the slope of the tangent line to the curve of the function at any given point. Derivatives can be computed using various rules, such as the power rule, product rule, and quotient rule, depending on the form of the function.

Cosecant Function (csc)

The cosecant function, denoted as csc(x), is the reciprocal of the sine function, defined as csc(x) = 1/sin(x). It is important in calculus when dealing with trigonometric functions, especially when finding derivatives. Understanding how to differentiate csc(x) and its properties is essential for solving problems involving trigonometric derivatives.

Quotient Rule

The quotient rule is a method for finding the derivative of a function that is the ratio of two other functions. If you have a function defined as f(x) = g(x)/h(x), the derivative is given by f'(x) = (g'(x)h(x) - g(x)h'(x)) / (h(x))². This rule is crucial when differentiating functions that involve division, such as the one presented in the question.

Find the derivatives of the functions in Exercises 1–42.𝔂 = 1 x² csc 22 x