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Ch. 3 - Derivatives
3์žฅ, ๋ฌธ์ œ 3.33

Find the derivatives of the functions in Exercises 1โ€“42.
_____
๐”‚ = / xยฒ + x
โˆš xยฒ

๊ฒ€์ฆ๋œ ๋‹จ๊ณ„๋ณ„ ์•ˆ๋‚ด
1
Step 1: Simplify the given function. The function is ๐”‚ = xยฒ + xโˆšxยฒ. Notice that xโˆšxยฒ can be rewritten as x * x, which simplifies to xยฒ. Therefore, the function becomes ๐”‚ = xยฒ + xยฒ.
Step 2: Combine like terms. Since both terms are xยฒ, the function simplifies to ๐”‚ = 2xยฒ.
Step 3: Differentiate the simplified function. To find the derivative of ๐”‚ = 2xยฒ, apply the power rule. The power rule states that the derivative of x^n is n*x^(n-1).
Step 4: Apply the power rule to each term. For the term 2xยฒ, the derivative is 2 * 2 * x^(2-1), which simplifies to 4x.
Step 5: Write the final expression for the derivative. The derivative of the function ๐”‚ = 2xยฒ is ๐”‚' = 4x.

๋น„์Šทํ•œ ๋ฌธ์ œ์— ๋Œ€ํ•œ ๊ฒ€์ฆ๋œ ์˜์ƒ ๋‹ต๋ณ€:

์ด ์˜์ƒ ํ•ด๋ฒ•์€ ์œ„ ๋ฌธ์ œ์— ๋„์›€์ด ๋œ๋‹ค๊ณ  ํŠœํ„ฐ๋“ค์ด ์ถ”์ฒœํ•œ ๊ฒƒ์ž…๋‹ˆ๋‹ค.
์˜์ƒ ๊ธธ์ด:
4m
๋„์›€์ด ๋˜์—ˆ๋‚˜์š”?

์ฃผ์š” ๊ฐœ๋…

์งˆ๋ฌธ์— ์˜ฌ๋ฐ”๋ฅด๊ฒŒ ๋‹ตํ•˜๊ธฐ ์œ„ํ•ด ๋ฐ˜๋“œ์‹œ ์ดํ•ดํ•ด์•ผ ํ•˜๋Š” ํ•ต์‹ฌ ๊ฐœ๋…๋“ค์€ ๋‹ค์Œ๊ณผ ๊ฐ™์Šต๋‹ˆ๋‹ค.

Derivatives

The derivative of a function measures how the function's output value changes as its input value changes. It is a fundamental concept in calculus, representing the slope of the tangent line to the curve of the function at any given point. Derivatives can be computed using various rules, such as the power rule, product rule, and quotient rule, depending on the form of the function.
์ถ”์ฒœ ์˜์ƒ:

Quotient Rule

The quotient rule is a method for finding the derivative of a function that is the ratio of two other functions. If you have a function defined as f(x) = g(x)/h(x), the derivative f'(x) is given by (g'(x)h(x) - g(x)h'(x)) / (h(x))ยฒ. This rule is essential when differentiating functions that involve division, as seen in the given problem.
์ถ”์ฒœ ์˜์ƒ:
06:43
The Quotient Rule

Simplifying Functions

Before differentiating complex functions, it is often helpful to simplify them. This can involve factoring, combining like terms, or rewriting expressions in a more manageable form. In the context of the given function, simplifying the expression can make it easier to apply the derivative rules accurately and efficiently.
์ถ”์ฒœ ์˜์ƒ:
6:36
Simplifying Trig Expressions
๊ด€๋ จ ์‹ค์ฒœ
๊ต๊ณผ์„œ ์งˆ๋ฌธ

Find the first and second derivatives of the functions in Exercises 33โ€“38.


w = ((1 + 3z) / 3z) (3 โˆ’ z)

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๊ต๊ณผ์„œ ์งˆ๋ฌธ

A balloon and a bicycle A balloon is rising vertically above a level, straight road at a constant rate of 1 ft/sec. Just when the balloon is 65 ft above the ground, a bicycle moving at a constant rate of 17 ft/sec passes under it. How fast is the distance s(t) between the bicycle and the balloon increasing 3 sec later?

235
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๊ต๊ณผ์„œ ์งˆ๋ฌธ

Derivative Calculations


In Exercises 1โ€“12, find the first and second derivatives.


y = 6xยฒ โˆ’ 10x โˆ’ 5xโปยฒ

246
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๊ต๊ณผ์„œ ์งˆ๋ฌธ

Estimating height of a building A surveyor, standing 30 ft from the base of a building, measures the angle of elevation to the top of the building to be 75ยฐ. How accurately must the angle be measured for the percentage error in estimating the height of the building to be less than 4%?

227
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๊ต๊ณผ์„œ ์งˆ๋ฌธ

One-Sided Derivatives


Compute the right-hand and left-hand derivatives as limits to show that the functions in Exercises 37โ€“40 are not differentiable at the point P.

254
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๊ต๊ณผ์„œ ์งˆ๋ฌธ

Second Derivatives


In Exercises 19โ€“26, use implicit differentiation to find dy/dx and then dยฒy/dxยฒ. Write the solutions in terms of x and y only.


yยฒ โ€“ 2x = 1 โ€“ 2y

269
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