Checking the Mean Value Theorem

Which of the functions in Exercises 7–12 satisfy the hypotheses of the Mean Value Theorem on the given interval, and which do not? Give reasons for your answers.

f(x) = x²ᐟ³, [−1, 8]

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Step 1: Recall the Mean Value Theorem (MVT), which states that if a function f is continuous on the closed interval [a, b] and differentiable on the open interval (a, b), then there exists at least one c in (a, b) such that f'(c) = (f(b) - f(a)) / (b - a).

Step 2: Check the continuity of f(x) = x^(2/3) on the interval [-1, 8]. A function is continuous if it has no breaks, jumps, or holes in the interval. Since x^(2/3) is a real-valued function for all x, it is continuous on [-1, 8].

Step 3: Check the differentiability of f(x) = x^(2/3) on the open interval (-1, 8). A function is differentiable at a point if it has a defined derivative at that point. Calculate the derivative f'(x) = (2/3)x^(-1/3).

Step 4: Analyze the derivative f'(x) = (2/3)x^(-1/3) for differentiability. The derivative is undefined at x = 0 because it involves division by zero. Therefore, f(x) is not differentiable at x = 0, which lies within the interval (-1, 8).

Step 5: Conclude that since f(x) = x^(2/3) is not differentiable at x = 0, it does not satisfy the hypotheses of the Mean Value Theorem on the interval [-1, 8].

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주요 개념

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Mean Value Theorem

The Mean Value Theorem (MVT) states that for a function f that is continuous on a closed interval [a, b] and differentiable on the open interval (a, b), there exists at least one point c in (a, b) such that f'(c) equals the average rate of change over [a, b]. This theorem helps in understanding the behavior of functions and is crucial for determining if a function meets its conditions.

Continuity

Continuity of a function on an interval means that the function has no breaks, jumps, or holes in that interval. For the Mean Value Theorem to apply, the function must be continuous on the closed interval [a, b]. In the context of the function f(x) = x²ᐟ³, we need to check if it is continuous on the interval [-1, 8].

Differentiability

Differentiability refers to the existence of a derivative at each point in an interval. For the Mean Value Theorem, the function must be differentiable on the open interval (a, b). For f(x) = x²ᐟ³, we must determine if the derivative exists for all x in (-1, 8), noting that differentiability implies continuity, but not vice versa.

Checking the Mean Value TheoremWhich of the functions in Exercises 7–12 satisfy the hypotheses of the Mean Value Theorem on the given interval, and which do not? Give reasons for your answers.f(x) = x²ᐟ³, [−1, 8]