Finding Position from Velocity or Acceleration

Exercises 41–44 give the velocity v = ds/dt and initial position of an object moving along a coordinate line. Find the object’s position at time t.

v = 9.8t + 5, s(0) = 10

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Start by recognizing that the velocity function v(t) = \(\frac{ds}{dt}\) = 9.8t + 5 is the derivative of the position function s(t). To find the position function, we need to integrate the velocity function with respect to time t.

Set up the integral of the velocity function: \(s(t) = \int (9.8t + 5) \, dt\).

Integrate the function: \(s(t) = \int 9.8t \, dt + \int 5 \, dt\).

Calculate each integral separately: \(\int 9.8t \, dt = 4.9t^2\) and \(\int 5 \, dt = 5t\). Combine these results to get the general form of the position function: \(s(t) = 4.9t^2 + 5t + C\), where C is the constant of integration.

Use the initial condition s(0) = 10 to solve for C. Substitute t = 0 into the position function: \(10 = 4.9(0)^2 + 5(0) + C\). Solve for C to find its value, and then substitute back into the position function to find the specific position function s(t).

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주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Integration

Integration is the process of finding the antiderivative or the area under a curve. In this context, integrating the velocity function v = ds/dt gives the position function s(t). This is because velocity is the derivative of position, so integrating velocity with respect to time will yield the position function.

Initial Conditions

Initial conditions are values that specify the state of a system at a particular time, often used to solve differential equations. Here, s(0) = 10 is the initial position of the object at time t = 0. This information is crucial for determining the constant of integration when finding the position function from the velocity function.

Definite and Indefinite Integrals

Indefinite integrals represent a family of functions and include a constant of integration, while definite integrals calculate the area under a curve between two points. In this problem, we use an indefinite integral to find the general form of the position function, and the initial condition helps determine the specific constant, giving the exact position function.

Finding Position from Velocity or AccelerationExercises 41–44 give the velocity v = ds/dt and initial position of an object moving along a coordinate line. Find the object’s position at time t.v = 9.8t + 5, s(0) = 10