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Ch. 5 - Integrals
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077당신이 사용하는 게 아니라요?교과서 변경
5장, 문제 5.PE.68

Evaluate the integrals in Exercises 47–68.


∫₀^π/4 sec²x / (1 + 7 tan x)²/³ dx

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1
Identify the integral to solve: \(\int_0^{\pi/4} \frac{\sec^2 x}{(1 + 7 \tan x)^{2/3}} \, dx\).
Recognize that the presence of \(\sec^2 x\) and \(\tan x\) suggests using the substitution \(u = 1 + 7 \tan x\) to simplify the integral.
Compute the differential \(du\): since \(u = 1 + 7 \tan x\), then \(du = 7 \sec^2 x \, dx\), which implies \(\sec^2 x \, dx = \frac{du}{7}\).
Change the limits of integration from \(x\) to \(u\): when \(x = 0\), \(u = 1 + 7 \tan 0 = 1\); when \(x = \frac{\pi}{4}\), \(u = 1 + 7 \tan \frac{\pi}{4} = 1 + 7 = 8\).
Rewrite the integral in terms of \(u\): \(\int_1^8 \frac{1}{u^{2/3}} \cdot \frac{1}{7} \, du = \frac{1}{7} \int_1^8 u^{-2/3} \, du\), which is now a standard power integral.

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주요 개념

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