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Ch. 7 - Transcendental Functions
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077당신이 사용하는 게 아니라요?교과서 변경
7장, 문제 7.P.118

118. A particle is traveling upward and to the right along the curve y=ln(x). Its x-coordinate is increasing at the rate (dx/dt)=√x m/sec. At what rate is the y-coordinate changing at the point (e², 2)?

검증된 단계별 안내
1
Identify the given information: The particle moves along the curve \(y = \ln(x)\), and the rate of change of the x-coordinate with respect to time is given by \(\frac{dx}{dt} = \sqrt{x}\) meters per second.
Recall that the rate of change of the y-coordinate with respect to time, \(\frac{dy}{dt}\), can be found using the chain rule: \(\frac{dy}{dt} = \frac{dy}{dx} \cdot \frac{dx}{dt}\).
Calculate \(\frac{dy}{dx}\) by differentiating \(y = \ln(x)\) with respect to \(x\): \(\frac{dy}{dx} = \frac{1}{x}\).
Evaluate \(\frac{dy}{dx}\) and \(\frac{dx}{dt}\) at the point \((e^{2}, 2)\): Substitute \(x = e^{2}\) into both expressions to find their values at that point.
Multiply the values found in the previous step to get \(\frac{dy}{dt}\) at the point \((e^{2}, 2)\): \(\frac{dy}{dt} = \frac{1}{e^{2}} \times \sqrt{e^{2}}\).

비슷한 문제에 대한 검증된 영상 답변:

이 영상 해법은 위 문제에 도움이 된다고 튜터들이 추천한 것입니다.
영상 길이:
2m

주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Related Rates

Related rates problems involve finding the rate at which one quantity changes by relating it to the rate of change of another quantity through their functional relationship. Here, the rates of change of x and y with respect to time are connected via the curve equation.
추천 영상:
가이드 코스
04:16
Intro To Related Rates

Chain Rule in Differentiation

The chain rule allows differentiation of composite functions. Since y = ln(x) depends on x, which in turn depends on time t, dy/dt is found by multiplying dy/dx by dx/dt, linking the rates of change through the chain rule.
추천 영상:
05:02
Intro to the Chain Rule

Properties of the Natural Logarithm Function

The natural logarithm function y = ln(x) has a derivative dy/dx = 1/x. This derivative is essential to find how y changes with respect to x, which is then used to determine the rate of change of y with respect to time.
추천 영상:
가이드 코스
06:21
Properties of Functions