Skip to main content
Ch. 7 - Transcendental Functions
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077당신이 사용하는 게 아니라요?교과서 변경
7장, 문제 7.AAE.13

13. For what x>0 does x^(x^x) = (x^x)^x? Give reasons for your answer.

검증된 단계별 안내
1
Start by writing the given equation clearly: \(x^{x^{x}} = (x^{x})^{x}\) for \(x > 0\).
Rewrite the right-hand side using the power of a power rule: \((x^{x})^{x} = x^{x \cdot x} = x^{x^{2}}\).
Now the equation becomes \(x^{x^{x}} = x^{x^{2}}\). Since the bases are the same and \(x > 0\), set the exponents equal: \(x^{x} = x^{2}\).
Rewrite the equation \(x^{x} = x^{2}\) by taking the natural logarithm of both sides: \(\ln(x^{x}) = \ln(x^{2})\).
Use the logarithm power rule to simplify: \(x \ln(x) = 2 \ln(x)\). Since \(x > 0\), consider cases where \(\ln(x) \neq 0\) and solve for \(x\).

비슷한 문제에 대한 검증된 영상 답변:

이 영상 해법은 위 문제에 도움이 된다고 튜터들이 추천한 것입니다.
영상 길이:
3m

주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Properties of Exponents

Understanding how to manipulate and simplify expressions with exponents is crucial. Key rules include (a^b)^c = a^(bc) and a^b * a^c = a^(b+c). These properties help rewrite and compare expressions like x^(x^x) and (x^x)^x by expressing them with a common base or exponent form.
추천 영상:
가이드 코스
06:21
Properties of Functions

Exponentiation with Variable Exponents

Exponentiation where the exponent itself is a function of the variable, such as x^x or x^(x^x), requires careful handling. Recognizing the hierarchy of operations and how to interpret nested exponents is essential to correctly simplify and analyze the expressions.
추천 영상:
7:39
Introduction to Exponent Rules

Equation Solving and Domain Considerations

Solving the equation x^(x^x) = (x^x)^x involves setting the expressions equal and simplifying to find x > 0. Considering the domain ensures the expressions are defined, and applying logarithms or exponent rules helps isolate x and determine all valid solutions.
추천 영상:
5:02
Solving Logarithmic Equations