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Ch. 7 - Transcendental Functions
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077당신이 사용하는 게 아니라요?교과서 변경
7장, 문제 7.1.19

Each of Exercises 19–24 gives a formula for a function y=f(x) and shows the graphs of f and f^(-1). Find a formula for f^(-1) in each case.
f(x)=x²+1, x≥0
Graph showing function y = x² + 1 (x≥0) and its inverse y = √(x - 1) with labeled axes.

검증된 단계별 안내
1
Start with the given function: \(y = f(x) = x^{2} + 1\) where \(x \geq 0\).
To find the inverse function \(f^{-1}(x)\), first replace \(f(x)\) with \(y\): \(y = x^{2} + 1\).
Swap the variables \(x\) and \(y\) to find the inverse: \(x = y^{2} + 1\).
Solve this equation for \(y\): subtract 1 from both sides to get \(x - 1 = y^{2}\).
Since \(x \geq 0\) in the original function, take the positive square root to get \(y = \sqrt{x - 1}\), which is the formula for \(f^{-1}(x)\).

비슷한 문제에 대한 검증된 영상 답변:

이 영상 해법은 위 문제에 도움이 된다고 튜터들이 추천한 것입니다.
영상 길이:
3m

주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Inverse Functions

An inverse function reverses the effect of the original function, swapping inputs and outputs. If y = f(x), then x = f⁻¹(y). The graph of an inverse function is a reflection of the original function's graph across the line y = x.
추천 영상:
4:49
Inverse Cosine

Domain and Range Restrictions

To find an inverse function, the original function must be one-to-one, often requiring domain restrictions. Here, f(x) = x² + 1 is restricted to x ≥ 0 to ensure it is invertible, as the parabola is not one-to-one over all real numbers.
추천 영상:
가이드 코스
5:10
Finding the Domain and Range of a Graph

Finding the Inverse Function Algebraically

To find f⁻¹(x), replace f(x) with y, swap x and y, then solve for y. For f(x) = x² + 1 with x ≥ 0, swapping gives x = y² + 1, so y = √(x - 1), which matches the inverse function shown in the graph.
추천 영상:
4:49
Inverse Cosine