Find the values in Exercises 9–12.
9. sin(arccos((√2)/2))

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Recognize that the expression involves a composition of trigonometric functions: \( \sin(\arccos(x)) \). Here, \( x = \frac{\sqrt{2}}{2} \).

Recall the definition of \( \arccos(x) \): it is the angle \( \theta \) such that \( \cos(\theta) = x \) and \( \theta \) lies in the range \( [0, \pi] \). So, \( \arccos\left(\frac{\sqrt{2}}{2}\right) = \theta \) where \( \cos(\theta) = \frac{\sqrt{2}}{2} \).

Use the Pythagorean identity for sine and cosine: \( \sin^2(\theta) + \cos^2(\theta) = 1 \). Since \( \cos(\theta) = \frac{\sqrt{2}}{2} \), substitute this value to find \( \sin(\theta) \).

Calculate \( \sin(\theta) = \sqrt{1 - \cos^2(\theta)} = \sqrt{1 - \left(\frac{\sqrt{2}}{2}\right)^2} \).

Determine the sign of \( \sin(\theta) \) based on the range of \( \theta = \arccos\left(\frac{\sqrt{2}}{2}\right) \), which lies between 0 and \( \pi \), where sine is non-negative.

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주요 개념

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Inverse Trigonometric Functions

Inverse trigonometric functions, like arccos, return the angle whose trigonometric function equals a given value. For example, arccos(x) gives the angle θ such that cos(θ) = x, typically within the range [0, π]. Understanding these functions helps in converting values back to angles.

Trigonometric Identities

Trigonometric identities relate the sine, cosine, and other trig functions of angles. The Pythagorean identity, sin²θ + cos²θ = 1, is especially useful for finding one function value when the other is known, enabling the evaluation of expressions like sin(arccos(x)).

Evaluating Composite Trigonometric Expressions

Evaluating expressions like sin(arccos(x)) involves interpreting the inner function as an angle and then applying trig identities or geometric reasoning to find the outer function's value. This often requires understanding the domain and range of the inverse function and the sign of the resulting sine value.

Find the values in Exercises 9–12.9. sin(arccos((√2)/2))