Skip to main content
Ch. 7 - Transcendental Functions
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077당신이 사용하는 게 아니라요?교과서 변경
7장, 문제 7.3.117

In Exercises 115–126, use logarithmic differentiation or the method in Example 6 to find the derivative of y with respect to the given independent variable.
117. y = (√t)ᵗ

검증된 단계별 안내
1
Rewrite the function to a form that is easier to differentiate using logarithmic differentiation. Start by expressing the function as \(y = (\sqrt{t})^{t} = (t^{1/2})^{t} = t^{t/2}\).
Take the natural logarithm of both sides to simplify the exponentiation: \(\ln y = \ln \left(t^{t/2}\right)\).
Use the logarithm power rule to bring down the exponent: \(\ln y = \frac{t}{2} \ln t\).
Differentiate both sides with respect to \(t\). Remember that \(y\) is a function of \(t\), so use implicit differentiation on the left side: \(\frac{1}{y} \frac{dy}{dt} = \frac{d}{dt} \left( \frac{t}{2} \ln t \right)\).
Apply the product rule to differentiate the right side: \(\frac{d}{dt} \left( \frac{t}{2} \ln t \right) = \frac{1}{2} \ln t + \frac{t}{2} \cdot \frac{1}{t}\). Then multiply both sides by \(y\) to solve for \(\frac{dy}{dt}\).

비슷한 문제에 대한 검증된 영상 답변:

이 영상 해법은 위 문제에 도움이 된다고 튜터들이 추천한 것입니다.
영상 길이:
4m
도움이 되었나요?

주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Logarithmic Differentiation

Logarithmic differentiation is a technique used to differentiate functions where the variable appears both in the base and the exponent. By taking the natural logarithm of both sides, the expression simplifies, allowing the use of implicit differentiation and product or chain rules more easily.
추천 영상:
06:30
Logarithmic Differentiation

Chain Rule

The chain rule is a fundamental differentiation rule used when differentiating composite functions. It states that the derivative of a composite function is the derivative of the outer function evaluated at the inner function times the derivative of the inner function.
추천 영상:
05:02
Intro to the Chain Rule

Properties of Logarithms

Properties of logarithms, such as log(a^b) = b log(a), help simplify expressions before differentiation. Applying these properties transforms complicated exponentials into products, making differentiation more straightforward.
추천 영상:
05:36
Change of Base Property