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Ch. 7 - Transcendental Functions
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077당신이 사용하는 게 아니라요?교과서 변경
7장, 문제 7.P.29

In Exercises 25–30, use logarithmic differentiation to find the derivative of y with respect to the appropriate variable.
29. y = (sin θ)^√θ

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Start by taking the natural logarithm of both sides of the equation to simplify the differentiation process: \(\ln y = \ln \left( (\sin \theta)^{\sqrt{\theta}} \right)\).
Use the logarithm power rule to bring the exponent down: \(\ln y = \sqrt{\theta} \cdot \ln (\sin \theta)\).
Differentiate both sides with respect to \(\theta\). Remember to use implicit differentiation on the left side and the product rule on the right side: \(\frac{1}{y} \frac{dy}{d\theta} = \frac{d}{d\theta} \left( \sqrt{\theta} \cdot \ln (\sin \theta) \right)\).
Apply the product rule to the right side: \(\frac{d}{d\theta} \left( \sqrt{\theta} \right) \cdot \ln (\sin \theta) + \sqrt{\theta} \cdot \frac{d}{d\theta} \left( \ln (\sin \theta) \right)\).
Calculate each derivative separately: \(\frac{d}{d\theta} \left( \sqrt{\theta} \right) = \frac{1}{2 \sqrt{\theta}}\) and \(\frac{d}{d\theta} \left( \ln (\sin \theta) \right) = \frac{\cos \theta}{\sin \theta} = \cot \theta\). Then substitute back into the expression and multiply both sides by \(y\) to solve for \(\frac{dy}{d\theta}\).

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이 영상 해법은 위 문제에 도움이 된다고 튜터들이 추천한 것입니다.
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주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Logarithmic Differentiation

Logarithmic differentiation is a technique used to differentiate functions where the variable appears both in the base and the exponent. By taking the natural logarithm of both sides, the expression simplifies, allowing the use of implicit differentiation and the properties of logarithms to find the derivative more easily.
추천 영상:
06:30
Logarithmic Differentiation

Chain Rule

The chain rule is a fundamental differentiation rule used when differentiating composite functions. It states that the derivative of a composite function is the derivative of the outer function evaluated at the inner function times the derivative of the inner function. This is essential when differentiating expressions like sin(θ) raised to a function of θ.
추천 영상:
05:02
Intro to the Chain Rule

Properties of Logarithms

Properties of logarithms, such as log(a^b) = b log(a), allow us to simplify complex expressions involving exponents. Applying these properties helps transform the original function into a form that is easier to differentiate, especially when the exponent itself is a function of the variable.
추천 영상:
05:36
Change of Base Property