Skip to main content
Ch. 7 - Transcendental Functions
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077당신이 사용하는 게 아니라요?교과서 변경
7장, 문제 7.7.25

In Exercises 25–36, find the derivative of y with respect to the appropriate variable.
25. y = sinh⁻¹(√x)

검증된 단계별 안내
1
Identify the function: \( y = \sinh^{-1}(\sqrt{x}) \). Here, \( y \) is the inverse hyperbolic sine of \( \sqrt{x} \).
Recall the derivative formula for the inverse hyperbolic sine function: \( \frac{d}{dx} \sinh^{-1}(u) = \frac{1}{\sqrt{1+u^2}} \cdot \frac{du}{dx} \), where \( u \) is a function of \( x \).
Set \( u = \sqrt{x} = x^{1/2} \). Then find \( \frac{du}{dx} \) using the power rule: \( \frac{du}{dx} = \frac{1}{2} x^{-1/2} \).
Apply the chain rule: \( \frac{dy}{dx} = \frac{1}{\sqrt{1 + (\sqrt{x})^2}} \cdot \frac{1}{2} x^{-1/2} \).
Simplify the expression inside the square root: \( (\sqrt{x})^2 = x \), so the derivative becomes \( \frac{dy}{dx} = \frac{1}{\sqrt{1 + x}} \cdot \frac{1}{2} x^{-1/2} \).

비슷한 문제에 대한 검증된 영상 답변:

이 영상 해법은 위 문제에 도움이 된다고 튜터들이 추천한 것입니다.
영상 길이:
4m

주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Inverse Hyperbolic Sine Function (sinh⁻¹)

The inverse hyperbolic sine function, sinh⁻¹(x), is the inverse of the hyperbolic sine function. It can be expressed as sinh⁻¹(x) = ln(x + √(x² + 1)), which helps in differentiating expressions involving sinh⁻¹.
추천 영상:
4:03
Inverse Sine

Chain Rule

The chain rule is a differentiation technique used when a function is composed of other functions. It states that the derivative of a composite function is the derivative of the outer function evaluated at the inner function times the derivative of the inner function.
추천 영상:
05:02
Intro to the Chain Rule

Derivative of Square Root Function

The square root function, √x, can be written as x^(1/2). Its derivative is (1/2)x^(-1/2), which is essential when differentiating expressions where the square root is inside another function.
추천 영상: