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Ch. 7 - Transcendental Functions
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077당신이 사용하는 게 아니라요?교과서 변경
7장, 문제 7.6.111

Verify the integration formulas in Exercises 111–114.
111. ∫ (arctan x) / x² dx = ln x - 1/2 ln(1 + x²) - arctan x / x + C

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Identify the integral to verify: \(\int \frac{\arctan x}{x^{2}} \, dx\).
Consider using integration by parts. Let \(u = \arctan x\) and \(dv = \frac{1}{x^{2}} dx\).
Compute the derivatives and integrals needed: \(du = \frac{1}{1 + x^{2}} dx\) and \(v = -\frac{1}{x}\).
Apply the integration by parts formula: \(\int u \, dv = uv - \int v \, du\), which gives \(-\frac{\arctan x}{x} - \int \left(-\frac{1}{x} \cdot \frac{1}{1 + x^{2}}\right) dx\).
Simplify the remaining integral \(\int \frac{1}{x(1 + x^{2})} dx\) by using partial fraction decomposition or substitution, then combine all parts to match the given formula.

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주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Integration by Parts

Integration by parts is a technique used to integrate products of functions. It is based on the product rule for differentiation and follows the formula ∫u dv = uv - ∫v du. Choosing appropriate u and dv is crucial to simplify the integral effectively.
추천 영상:
가이드 코스
06:18
Integration by Parts for Definite Integrals

Derivative and Integral of Inverse Trigonometric Functions

Understanding the derivatives and integrals of inverse trigonometric functions like arctan(x) is essential. For example, d/dx [arctan x] = 1/(1 + x²). This knowledge helps in manipulating integrals involving arctan(x) and recognizing patterns during integration.
추천 영상:
06:35
Derivatives of Other Inverse Trigonometric Functions

Logarithmic Integration and Simplification

Integrals often result in logarithmic expressions, especially when integrating rational functions. Recognizing when to rewrite expressions using logarithm properties, such as ln(a) - ln(b) = ln(a/b), aids in simplifying the final answer and verifying given formulas.
추천 영상:
7:30
Logarithms Introduction