Skip to main content
Ch. 8 - Techniques of Integration
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077당신이 사용하는 게 아니라요?교과서 변경
8장, 문제 8.8.34

The integrals in Exercises 1–34 converge. Evaluate the integrals without using tables.
∫₀^∞ dx / [(x + 1)(x² + 1)]

검증된 단계별 안내
1
Start by expressing the integrand \( \frac{1}{(x+1)(x^2+1)} \) as a sum of partial fractions. Set up the equation: \[ \frac{1}{(x+1)(x^2+1)} = \frac{A}{x+1} + \frac{Bx + C}{x^2 + 1} \] where \(A\), \(B\), and \(C\) are constants to be determined.
Multiply both sides of the equation by \( (x+1)(x^2+1) \) to clear the denominators, resulting in: \[ 1 = A(x^2 + 1) + (Bx + C)(x + 1) \]. Expand the right-hand side and collect like terms in powers of \(x\).
Equate the coefficients of corresponding powers of \(x\) on both sides to form a system of equations for \(A\), \(B\), and \(C\). Solve this system to find the values of these constants.
Rewrite the integral as the sum of integrals of the partial fractions: \[ \int_0^\infty \frac{dx}{(x+1)(x^2+1)} = \int_0^\infty \frac{A}{x+1} dx + \int_0^\infty \frac{Bx + C}{x^2 + 1} dx \].
Evaluate each integral separately. For \( \int \frac{1}{x+1} dx \), use the natural logarithm function. For \( \int \frac{x}{x^2 + 1} dx \), use substitution \( u = x^2 + 1 \). For \( \int \frac{1}{x^2 + 1} dx \), use the arctangent function. Then, apply the limits from 0 to \( \infty \) carefully to find the value of the original integral.

비슷한 문제에 대한 검증된 영상 답변:

이 영상 해법은 위 문제에 도움이 된다고 튜터들이 추천한 것입니다.
영상 길이:
12m
도움이 되었나요?

주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Improper Integrals

Improper integrals involve integration over an infinite interval or integrands with infinite discontinuities. To evaluate them, we take limits of definite integrals as the bounds approach infinity or the points of discontinuity. This ensures the integral converges to a finite value.
추천 영상:
11:11
Improper Integrals: Infinite Intervals

Partial Fraction Decomposition

Partial fraction decomposition breaks a complex rational function into simpler fractions that are easier to integrate. For example, a fraction with a quadratic and linear factor in the denominator can be expressed as a sum of simpler rational functions, facilitating straightforward integration.
추천 영상:
10:07
Partial Fraction Decomposition: Distinct Linear Factors

Integration of Rational Functions

Integrating rational functions often involves recognizing standard integral forms and applying techniques like substitution or partial fractions. Understanding how to integrate terms like 1/(x² + 1) and 1/(x + a) is essential for solving integrals involving polynomial denominators.
추천 영상:
6:04
Intro to Rational Functions