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Ch. 8 - Techniques of Integration
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077당신이 사용하는 게 아니라요?교과서 변경
8장, 문제 8.1.42

The integrals in Exercises 1–44 are in no particular order. Evaluate each integral using any algebraic method, trigonometric identity, or substitution you think is appropriate.
∫ ((2ˣ - 1) / 3ˣ) dx

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Rewrite the integrand to express it in terms of exponential functions with the same base. Note that \$3^x\( can be written as \(e^{x \ln(3)}\) and \)2^x$ as \(e^{x \ln(2)}\). So, rewrite the integrand as \(\frac{2^x - 1}{3^x} = \frac{e^{x \ln(2)} - 1}{e^{x \ln(3)}}\).
Simplify the expression by splitting the fraction into two terms: \(\frac{e^{x \ln(2)}}{e^{x \ln(3)}} - \frac{1}{e^{x \ln(3)}} = e^{x (\ln(2) - \ln(3))} - e^{-x \ln(3)}\).
Recognize that \(\ln(2) - \ln(3) = \ln\left(\frac{2}{3}\right)\), so the integrand becomes \(e^{x \ln(\frac{2}{3})} - e^{-x \ln(3)}\).
Set up the integral as the sum of two integrals: \(\int e^{x \ln(\frac{2}{3})} dx - \int e^{-x \ln(3)} dx\).
Integrate each term separately using the formula \(\int e^{ax} dx = \frac{1}{a} e^{ax} + C\). For the first integral, \(a = \ln\left(\frac{2}{3}\right)\), and for the second, \(a = -\ln(3)\). Write the antiderivatives accordingly.

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주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

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