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Ch. 8 - Techniques of Integration
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077당신이 사용하는 게 아니라요?교과서 변경
8장, 문제 8.1.18

The integrals in Exercises 1–44 are in no particular order. Evaluate each integral using any algebraic method, trigonometric identity, or substitution you think is appropriate.
∫ (2^(√y) dy) / 2√y

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Start by examining the integral: \(\int \frac{2^{\sqrt{y}}}{2\sqrt{y}} \, dy\). Notice that the expression involves \(\sqrt{y}\) both in the exponent and the denominator, suggesting a substitution involving \(\sqrt{y}\) might simplify the integral.
Let \(u = \sqrt{y} = y^{1/2}\). Then, differentiate both sides with respect to \(y\) to find \(du\) in terms of \(dy\): \(u = y^{1/2} \implies du = \frac{1}{2\sqrt{y}} dy\).
Rearrange the differential to express \(dy\) in terms of \(du\): from \(du = \frac{1}{2\sqrt{y}} dy\), multiply both sides by \(2\sqrt{y}\) to get \(dy = 2\sqrt{y} \, du\).
Substitute \(u\) and \(dy\) back into the integral: replace \(2^{\sqrt{y}}\) with \$2^u\( and \)dy$ with \(2\sqrt{y} \, du\). Notice that the \(2\sqrt{y}\) in the denominator and numerator will cancel out, simplifying the integral to \(\int 2^u \, du\).
Now, integrate \(\int 2^u \, du\) using the formula for integrating exponential functions with base \(a\): \(\int a^u \, du = \frac{a^u}{\ln(a)} + C\). Apply this formula with \(a=2\) to find the antiderivative in terms of \(u\), then substitute back \(u = \sqrt{y}\) to express the answer in terms of \(y\).

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주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Integration by Substitution

Integration by substitution is a method used to simplify integrals by changing variables. It involves identifying a part of the integrand as a new variable, differentiating it, and rewriting the integral in terms of this variable to make it easier to evaluate.
추천 영상:
04:27
Substitution With an Extra Variable

Exponential Functions with Variable Exponents

Exponential functions where the exponent is a function of the variable, such as 2^(√y), require careful handling. Understanding how to differentiate and integrate such functions often involves rewriting the expression using properties of exponents and logarithms.
추천 영상:
6:13
Exponential Functions

Algebraic Manipulation of Integrands

Algebraic manipulation involves rewriting the integrand to a more convenient form before integrating. This can include factoring, simplifying radicals, or expressing terms in a way that aligns with substitution or known integral formulas.
추천 영상:
05:22
Completing the Square to Rewrite the Integrand