Find all values of x satisfying the given conditions. y1 = x - 1, y2 = x + 4 and y1y2 = 14
Ch. 1 - Equations and Inequalities

2장, 문제 113
In Exercises 109–114, find the x-intercept(s) of the graph of each equation. Use the x-intercepts to match the equation with its graph. The graphs are shown in [- 10, 10, 1] by [- 10, 10, 1] viewing rectangles and labeled (a) through (f). y = x2 - 2x + 2






검증된 단계별 안내1
To find the x-intercepts of the graph of the equation \( y = x^2 - 2x + 2 \), set \( y = 0 \). This is because the x-intercepts occur where the graph crosses the x-axis, and at these points, the value of \( y \) is zero.
The equation becomes \( 0 = x^2 - 2x + 2 \). This is a quadratic equation, so we will solve it using the quadratic formula: \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \), where \( a \), \( b \), and \( c \) are the coefficients from the standard form of the quadratic equation \( ax^2 + bx + c = 0 \).
Identify the coefficients: \( a = 1 \), \( b = -2 \), and \( c = 2 \). Substitute these values into the quadratic formula: \( x = \frac{-(-2) \pm \sqrt{(-2)^2 - 4(1)(2)}}{2(1)} \).
Simplify the discriminant (the expression under the square root): \( (-2)^2 - 4(1)(2) = 4 - 8 = -4 \). Since the discriminant is negative, the equation has no real solutions, meaning the graph does not cross the x-axis. Instead, the solutions are complex numbers.
Conclude that the graph of \( y = x^2 - 2x + 2 \) has no x-intercepts. This means the parabola does not intersect the x-axis, and its vertex lies above the x-axis because the parabola opens upwards (as \( a > 0 \)).

비슷한 문제에 대한 검증된 영상 답변:
이 영상 해법은 위 문제에 도움이 된다고 튜터들이 추천한 것입니다.
영상 길이:
7m주요 개념
질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.
X-Intercept
The x-intercept of a graph is the point where the graph intersects the x-axis. This occurs when the value of y is zero. To find the x-intercept(s) of an equation, you set y equal to zero and solve for x. In the context of the given equation, this means solving the quadratic equation x^2 - 2x + 2 = 0.
추천 영상:
Graphing Intercepts
Quadratic Equations
A quadratic equation is a polynomial equation of the form ax^2 + bx + c = 0, where a, b, and c are constants, and a is not zero. The solutions to a quadratic equation can be found using various methods, including factoring, completing the square, or applying the quadratic formula. Understanding the nature of the roots (real or complex) is essential for determining the x-intercepts.
추천 영상:
Introduction to Quadratic Equations
Graphing Quadratics
Graphing a quadratic function involves plotting a parabola, which can open upwards or downwards depending on the sign of the leading coefficient (a). The vertex of the parabola represents the maximum or minimum point, and the x-intercepts indicate where the graph crosses the x-axis. Analyzing the graph helps in visualizing the solutions and understanding the behavior of the function.
추천 영상:
Solving Quadratic Equations Using The Quadratic Formula
관련 실천
교과서 질문
983
views
교과서 질문
Find all values of x satisfying the given conditions. y = 2x2 - 3x and y = 2
1056
views
교과서 질문
Solve and graph the solution set on a number line: (2x−3)/4 ≥ 3x/4 + 1/2
737
views
교과서 질문
In Exercises 109–114, find the x-intercept(s) of the graph of each equation. Use the x-intercepts to match the equation with its graph. The graphs are shown in [- 10, 10, 1] by [- 10, 10, 1] viewing rectangles and labeled (a) through (f). y = x2 - 4x - 5
915
views
교과서 질문
Find all values of x satisfying the given conditions. y = 5x2 + 3x and y = 2
692
views
교과서 질문
In Exercises 109–114, find the x-intercept(s) of the graph of each equation. Use the x-intercepts to match the equation with its graph. The graphs are shown in [- 10, 10, 1] by [- 10, 10, 1] viewing rectangles and labeled (a) through (f). y = - (x + 1)2 + 4
923
views
