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Ch. 1 - Equations and Inequalities
Lial - College Algebra 13th Edition
Lial13th EditionCollege AlgebraISBN: 9780136881063당신이 사용하는 게 아니라요?교과서 변경
2장, 문제 81b

For each equation, (b) solve for y in terms of x. See Example 8.
2x2+4xy3y2=22x^2 + 4xy - 3y^2 = 2

검증된 단계별 안내
1
Start with the given equation: \(2x^{2} + 4xy - 3y^{2} = 2\).
Rewrite the equation to isolate terms involving \(y\): \(4xy - 3y^{2} = 2 - 2x^{2}\).
Recognize this as a quadratic equation in terms of \(y\): \(-3y^{2} + 4xy - (2 - 2x^{2}) = 0\).
Use the quadratic formula to solve for \(y\), where \(a = -3\), \(b = 4x\), and \(c = -(2 - 2x^{2})\). The formula is \(y = \frac{-b \pm \sqrt{b^{2} - 4ac}}{2a}\).
Substitute the values of \(a\), \(b\), and \(c\) into the quadratic formula and simplify under the square root to express \(y\) explicitly in terms of \(x\).

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