Skip to main content
Ch. 1 - Equations and Inequalities
Lial - College Algebra 13th Edition
Lial13th EditionCollege AlgebraISBN: 9780136881063당신이 사용하는 게 아니라요?교과서 변경
2장, 문제 114

Solve each equation or inequality.
85x2|8-5x| ≥ 2

검증된 단계별 안내
1
Recognize that the inequality involves an absolute value expression: \(|8 - 5x| \geq 2\). Recall that for any expression \(A\), \(|A| \geq k\) means \(A \geq k\) or \(A \leq -k\) when \(k > 0\).
Set up two separate inequalities based on the definition of absolute value inequalities: 1) \(8 - 5x \geq 2\) 2) \(8 - 5x \leq -2\)
Solve the first inequality \(8 - 5x \geq 2\) by isolating \(x\): Subtract 8 from both sides: \(-5x \geq 2 - 8\) Simplify the right side: \(-5x \geq -6\) Divide both sides by \(-5\), remembering to reverse the inequality sign because you are dividing by a negative number: \(x \leq \frac{-6}{-5}\)
Solve the second inequality \(8 - 5x \leq -2\) similarly: Subtract 8 from both sides: \(-5x \leq -2 - 8\) Simplify the right side: \(-5x \leq -10\) Divide both sides by \(-5\), reversing the inequality sign: \(x \geq \frac{-10}{-5}\)
Combine the two solution sets from steps 3 and 4 to express the final solution as a union of intervals where \(x\) satisfies either inequality.

비슷한 문제에 대한 검증된 영상 답변:

이 영상 해법은 위 문제에 도움이 된다고 튜터들이 추천한 것입니다.
영상 길이:
2m
도움이 되었나요?

주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Absolute Value Inequalities

Absolute value inequalities involve expressions where the distance of a number from zero is compared to another value. For |A| ≥ B, the solution includes values where A ≤ -B or A ≥ B, reflecting the two-sided nature of absolute value.
추천 영상:
06:07
Linear Inequalities

Solving Linear Inequalities

Solving linear inequalities requires isolating the variable while maintaining inequality direction. When multiplying or dividing by a negative number, the inequality sign must be reversed to preserve the inequality's truth.
추천 영상:
06:07
Linear Inequalities

Splitting Absolute Value Expressions

To solve |expression| ≥ number, split the inequality into two cases: one where the expression is greater than or equal to the number, and one where it is less than or equal to the negative of that number. Solve each case separately.
추천 영상:
05:45
Radical Expressions with Fractions