Work each problem. Elmer borrowed \$3150 from his brother Julio to pay for books and tuition. He agreed to repay Julio in 6 months with simple annual interest at 4%. How much will the interest amount to?
Ch. 1 - Equations and Inequalities

2장, 문제 59
Solve each equation. √3x=√(5x+1)-1
검증된 단계별 안내1
Start with the given equation: \(\sqrt{3x} = \sqrt{5x + 1} - 1\).
Isolate one of the square root terms by adding 1 to both sides: \(\sqrt{3x} + 1 = \sqrt{5x + 1}\).
Square both sides of the equation to eliminate the square roots: \(\left(\sqrt{3x} + 1\right)^2 = \left(\sqrt{5x + 1}\right)^2\).
Expand the left side using the formula \((a + b)^2 = a^2 + 2ab + b^2\): \(3x + 2\sqrt{3x} + 1 = 5x + 1\).
Simplify the equation and isolate the remaining square root term, then square both sides again to solve for \(x\).

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이 영상 해법은 위 문제에 도움이 된다고 튜터들이 추천한 것입니다.
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주요 개념
질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.
Square Root Equations
Square root equations involve variables under a radical sign. To solve them, isolate the square root expression and then square both sides to eliminate the radical. This process may introduce extraneous solutions, so checking all solutions in the original equation is essential.
추천 영상:
Imaginary Roots with the Square Root Property
Isolating Variables
Isolating the variable means manipulating the equation to get the variable alone on one side. This step is crucial before squaring both sides to avoid complicating the equation further. Proper isolation helps simplify the solving process and reduces errors.
추천 영상:
가이드 코스
Equations with Two Variables
Checking for Extraneous Solutions
Squaring both sides of an equation can introduce solutions that do not satisfy the original equation. These are called extraneous solutions. Always substitute the found solutions back into the original equation to verify which ones are valid.
추천 영상:
Restrictions on Rational Equations
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