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Ch. 1 - Equations and Inequalities
Lial - College Algebra 13th Edition
Lial13th EditionCollege AlgebraISBN: 9780136881063당신이 사용하는 게 아니라요?교과서 변경
2장, 문제 59

Solve each equation. √3x=√(5x+1)-1

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Start with the given equation: \(\sqrt{3x} = \sqrt{5x + 1} - 1\).
Isolate one of the square root terms by adding 1 to both sides: \(\sqrt{3x} + 1 = \sqrt{5x + 1}\).
Square both sides of the equation to eliminate the square roots: \(\left(\sqrt{3x} + 1\right)^2 = \left(\sqrt{5x + 1}\right)^2\).
Expand the left side using the formula \((a + b)^2 = a^2 + 2ab + b^2\): \(3x + 2\sqrt{3x} + 1 = 5x + 1\).
Simplify the equation and isolate the remaining square root term, then square both sides again to solve for \(x\).

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주요 개념

질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.

Square Root Equations

Square root equations involve variables under a radical sign. To solve them, isolate the square root expression and then square both sides to eliminate the radical. This process may introduce extraneous solutions, so checking all solutions in the original equation is essential.
추천 영상:
02:20
Imaginary Roots with the Square Root Property

Isolating Variables

Isolating the variable means manipulating the equation to get the variable alone on one side. This step is crucial before squaring both sides to avoid complicating the equation further. Proper isolation helps simplify the solving process and reduces errors.
추천 영상:
가이드 코스
05:28
Equations with Two Variables

Checking for Extraneous Solutions

Squaring both sides of an equation can introduce solutions that do not satisfy the original equation. These are called extraneous solutions. Always substitute the found solutions back into the original equation to verify which ones are valid.
추천 영상:
05:21
Restrictions on Rational Equations