Solve each equation. (2x-1)2/3+2(2x-1)1/3-3=0
Ch. 1 - Equations and Inequalities

2장, 문제 91
Solve each equation. (x-1)2/3+(x-1)1/3 -12 = 0
검증된 단계별 안내1
Start by making a substitution to simplify the equation. Let \( y = (x - 1)^{1/3} \). This means \( y^2 = (x - 1)^{2/3} \).
Rewrite the original equation \( (x-1)^{2/3} + (x-1)^{1/3} - 12 = 0 \) in terms of \( y \) as \( y^2 + y - 12 = 0 \).
Recognize that the equation \( y^2 + y - 12 = 0 \) is a quadratic equation in standard form. Use the quadratic formula \( y = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \) where \( a=1, b=1, c=-12 \) to find the values of \( y \).
After finding the values of \( y \), substitute back \( y = (x - 1)^{1/3} \) to get \( (x - 1)^{1/3} = y \).
Solve each resulting equation by cubing both sides to eliminate the cube root, giving \( x - 1 = y^3 \), and then solve for \( x \) by adding 1 to both sides.

비슷한 문제에 대한 검증된 영상 답변:
이 영상 해법은 위 문제에 도움이 된다고 튜터들이 추천한 것입니다.
영상 길이:
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주요 개념
질문에 올바르게 답하기 위해 반드시 이해해야 하는 핵심 개념들은 다음과 같습니다.
Rational Exponents
Rational exponents represent roots and powers simultaneously, where the numerator is the power and the denominator is the root. For example, x^(2/3) means the cube root of x squared. Understanding how to manipulate and simplify expressions with rational exponents is essential for solving the given equation.
추천 영상:
Rational Exponents
Substitution Method
The substitution method involves replacing a complex expression with a single variable to simplify the equation. In this problem, letting y = (x-1)^(1/3) transforms the equation into a quadratic form, making it easier to solve. After solving for y, substitute back to find x.
추천 영상:
Choosing a Method to Solve Quadratics
Solving Quadratic Equations
Quadratic equations are polynomial equations of degree two and can be solved by factoring, completing the square, or using the quadratic formula. Once the substitution reduces the original equation to a quadratic in y, these methods help find the roots, which then lead to the solutions for x.
추천 영상:
Solving Quadratic Equations by Factoring
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