Solve each equation using the quadratic formula. x2 = 2x - 5

Ch. 1 - Equations and Inequalities

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Lial 13th Edition

Ch. 1 - Equations and Inequalities

문제 55

2장, 문제 55

Solve each equation using the quadratic formula. x² = 2x - 5

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Rewrite the equation in standard quadratic form, which is \(ax^2 + bx + c = 0\). Start by moving all terms to one side: \(x^2 - 2x + 5 = 0\).

Identify the coefficients \(a\), \(b\), and \(c\) from the quadratic equation. Here, \(a = 1\), \(b = -2\), and \(c = 5\).

Recall the quadratic formula: \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\). This formula gives the solutions to any quadratic equation.

Substitute the values of \(a\), \(b\), and \(c\) into the quadratic formula: \(x = \frac{-(-2) \pm \sqrt{(-2)^2 - 4(1)(5)}}{2(1)}\).

Simplify inside the square root and the rest of the expression step-by-step to find the two possible values of \(x\).

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주요 개념

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Quadratic Equation Standard Form

A quadratic equation is typically written in the standard form ax² + bx + c = 0. To solve using the quadratic formula, the equation must first be rearranged so that all terms are on one side, setting the equation equal to zero.

Quadratic Formula

The quadratic formula x = (-b ± √(b² - 4ac)) / (2a) provides the solutions to any quadratic equation ax² + bx + c = 0. It uses the coefficients a, b, and c to find the roots, including real and complex solutions.

Discriminant and Nature of Roots

The discriminant, given by b² - 4ac, determines the nature of the roots of a quadratic equation. If positive, there are two distinct real roots; if zero, one real root; and if negative, two complex roots.