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Ch. R - Review of Basic Concepts
Lial - College Algebra 13th Edition
Lial13th EditionCollege AlgebraISBN: 9780136881063당신이 사용하는 게 아니라요?교과서 변경
1장, 문제 105

Evaluate each expression for p=-4, q=8, and r=-10. 5r / 2p-3r

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First, substitute the given values into the expression. The expression is \(\frac{5r}{2p - 3r}\), and the values are \(p = -4\), \(q = 8\), and \(r = -10\). Since \(q\) is not in the expression, focus on \(p\) and \(r\).
Replace \(r\) with \(-10\) and \(p\) with \(-4\) in the expression: \(\frac{5(-10)}{2(-4) - 3(-10)}\).
Simplify the numerator by multiplying: \(5 \times (-10) = -50\), so the numerator becomes \(-50\).
Simplify the denominator by performing the multiplications first: \(2 \times (-4) = -8\) and \(3 \times (-10) = -30\). Then substitute these back into the denominator: \(-8 - (-30)\).
Simplify the denominator by subtracting a negative number, which is equivalent to addition: \(-8 + 30\). Then, write the simplified expression as \(\frac{-50}{22}\).

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