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Ch. R - Review of Basic Concepts
Lial - College Algebra 13th Edition
Lial13th EditionCollege AlgebraISBN: 9780136881063당신이 사용하는 게 아니라요?교과서 변경
1장, 문제 109

Evaluate each expression for p=4p=-4, q=8q=8, and r=10r=-10. (p+2)23r2q\(\frac{-(p + 2)^2 - 3r}{2 - q}\)

검증된 단계별 안내
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First, substitute the given values into the expression: replace \( p \) with \( -4 \), \( q \) with \( 8 \), and \( r \) with \( -10 \) in the expression \( - (p+2)^2 - \frac{3r}{2} - q \).
Next, simplify inside the parentheses: calculate \( p + 2 \) by adding \( -4 + 2 \).
Then, square the result from the previous step to get \( (p+2)^2 \).
After that, multiply \( 3 \) by \( r \) and then divide by \( 2 \) to simplify the fraction \( \frac{3r}{2} \).
Finally, combine all parts of the expression by applying the negative sign to the squared term, subtracting the fraction, and then subtracting \( q \) to simplify the entire expression.

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주요 개념

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