Determine the molecular geometry for the following molecule: CHClO.
A
Trigonal pyramidal
B
T-shaped
C
Trigonal planar
D
Tetrahedral
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1
Identify the central atom in the molecule CHClO. Typically, carbon (C) is the central atom because it can form four bonds.
Count the total number of valence electrons around the central atom, including those from bonded atoms (H, Cl, and O). Carbon has 4 valence electrons, hydrogen has 1, chlorine has 7, and oxygen has 6.
Determine the number of electron groups (bonding and lone pairs) around the central atom. Since carbon usually forms four single bonds and has no lone pairs, count the bonds to H, Cl, and O.
Use the VSEPR (Valence Shell Electron Pair Repulsion) theory to predict the molecular geometry based on the number of electron groups. Four bonding groups with no lone pairs around carbon correspond to a tetrahedral electron geometry.
Consider the arrangement of atoms (not just electron pairs) to determine the molecular geometry. Since all four substituents are bonded to carbon, the molecular geometry is tetrahedral.